 | Robert Potts - 1865 - 528 pages
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclides - 1865 - 402 pages
...draw a straight line AC, making any angle with AB, and in AC take any point D ; and take AC the same multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to CB. (i. 31.) Then AB shall be the part required to he out off. DEMONSTRATION Because ED is parallel... | |
 | John Playfair - Geometry - 1855 - 350 pages
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cut off from it ; join BC, and draw DE parallel to it: th«n AE is the part required to be cut off. Because CD is parallel to one of the sides of the triangle... | |
 | Euclid, Isaac Todhunter - Euclid's Elements - 1867 - 426 pages
...A draw a straight line AC, making any angle with AB; in AC tak e any point D, and take AC the same multiple of AD, that AB is of the part which is to...off from it ; join BC, and draw DE parallel to it. AE shall be the part required to be cut off. For, because ED is parallel to BC, one of the sides of... | |
 | Euclid, Isaac Todhunter - Euclid's Elements - 1867 - 424 pages
...point A draw a straight line AC, making any angle with AB; in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...off from it ; join BC, and draw DE parallel to it. AE shall be the part required to be cut off. For, because ED is parallel to BC, one of the sides of... | |
 | Robert Potts - 1868 - 434 pages
...draw a straight line AC, making any angle with AB; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...cut off from it ; join BC, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel to BC, one of the sides... | |
 | Euclid - 1876 - 240 pages
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part which is to...from it ; join BC, and draw DE parallel to it : then AK is the part required to be cut off. fa) VL 2. (6) V. 18. (c$ VD DEMONSTRATION. Because ED is parallel... | |
 | Robert Potts - Geometry - 1876 - 446 pages
...draw a straight line AC, making any angle with AB\ and in AC take any point D, and take ACtiie same multiple of AD, that AB is of the part which is to be cut off from it ; join BG, and draw DE parallel to CB. Then AE shall be the part required to be cut off. Because ED is parallel... | |
 | Isaac Sharpless - Geometry - 1879 - 282 pages
...any point D, and take AC so that it shall contain AD as many times as AB is to contain the part that is to be cut off from it; join BC, and draw DE parallel to it; then AE is the part to be cut off. Because ED is parallel to one of the sides of the triangle ABC (V. 2), CD : DA :: BE... | |
 | Isaac Todhunter - Euclid's Elements - 1880 - 426 pages
...point A draw a straight line AG, making any angle with AB; in AG take any point D, and take AC the same multiple of AD, that AB is of the part which is to...off from it ; join BC, and draw DE parallel to it. AE shall be the part required to be cut off. For, because ED is parallel to BC, [Construction. one... | |
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AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. 
