 | Euclides - Euclid's Elements - 1881 - 236 pages
...angle BAC, with AB. In AC take any point D, and make AC the same multiple of AD, that AB is of the part to be cut off from it Join BC, and draw DE parallel to E/-AB C B. The part AE is the part required to be cut off from AB. Because ED is parallel to BC, one... | |
 | Isaac Sharpless - Geometry - 1882 - 292 pages
...point D, and from the point D along the line DC lay off AD the given number of times, to the point C; join BC, and draw DE parallel to it ; then AE is the part to be cut off. Because ED is parallel to one of the sides of the triangle ABC (V. 2), CD : DA : : BE... | |
 | Euclid, Isaac Todhunter - Euclid's Elements - 1883 - 426 pages
...line AG, making any angle with AB ; in^46?takeanypointZ>, andtake^4(7the same multiple of AD, that AS is of the part which is to be cut off from it ; join BO, and draw DE parallel to it. AE shall be the part required to be cut off. For, because ED is parallel... | |
 | Euclid - Mathematics, Greek - 1908 - 456 pages
...point A draw a straight line AC making any angle with AB; in AC take any point D, and take AC the same multiple of AD that AB is of the part which is to...to it : then AE is the part required to be cut off. Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as CD is to DA, so is BE... | |
 | Euclid - 452 pages
...point A draw a straight line AC making any angle with AB; in AC take any point D, and take AC the same multiple of AD that AB is of the part which is to...cut off from it; join BC, and draw DE parallel to it : PROPOSITIONS 9, 10 Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as... | |
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AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off. 
