| Euclid, Robert Simson - Geometry - 1821 - 514 pages
...draw a straight line AC making any angle with AB; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to be** ci t off from it: join BC, and draw DE parallel to cut it: then AE is the part required to be cut off.... | |
| Euclid, John Playfair - Euclid's Elements - 1826 - 326 pages
...and take AC A Mieh that it shall eontain AD, as oft as AB is to eontain the part, whieh is to be eut **off from it; join BC, and draw DE parallel to it: then AE is the part required to be** eut off. Beeause ED is parallel to one of the sides of the triangle ABC, viz. to BC, CD : DA " DE :... | |
| Robert Simson - Trigonometry - 1827 - 513 pages
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to be cut** oft' from it ; join BC, and draw DE parallel to it: then AE shall be the part required to be cut off.... | |
| John Playfair - Euclid's Elements - 1833 - 333 pages
...and take AC such that it shall contain AD, as oft as AB is to contain the part, which is to be cutoff **from it ; join BC, and draw DE parallel to it : then AE is the part required to be cut off.** Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, CD : DA : : DE : EA (2.... | |
| Euclides - 1834 - 518 pages
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...it ; join BC, and draw DE parallel to it : then AE** shall be the part required to be cut off. f The triangles ADB, ADC, being both equiangular to ABC,... | |
| Euclid - 1835 - 540 pages
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...to it: Then AE is the part required to be cut off.** Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as CD is to DA, so is1... | |
| Robert Simson - Trigonometry - 1835 - 513 pages
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to be cut off from it; join BC,** A and draw DE parallel to it : Then AE l\ is the part required to be cut off. / \ Because ED is parallel... | |
| John Playfair - Geometry - 1836 - 114 pages
...draw a straight line AC making any angle with AB ; and in AC take any point D, and takeAC the same **multiple of AD, that AB is of the part which is to...to it : then AE is the part required to be cut off.** Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as CD is to DA, so is (3.... | |
| Euclid - Geometry - 1837 - 410 pages
...book. t Draw a straight line AC making any angle with AB ; in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to be cut off from it** ; A join BC, and (I. 31.) draw DE parallel to it : AE N is the part required. T"\ Because ED is parallel... | |
| Andrew Bell - Euclid's Elements - 1837 - 240 pages
...with AB ; and in AC take any point D, and take AC the same multiple of AD, that AB is of the part A **•which is to be cut off from it ; join BC, and draw** l\ DE parallel to it ; then AE is the part required X/~V to be cut off. / \ Because ED is parallel... | |
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