| Christian Brothers - Business mathematics - 1888
...between 2809 sq. ft. Ï500 sy. ft., or У09 sg. it. 28'09 2500 50 3 502 = = 100 3 50x2 309 53 Ans. Since **the area of a rectangle is equal to the product of its length and** width, the width is equal to the area divided by the length. Therefore, the probable width of each... | |
| W. E. BYERLY - 1887
...two rectangles are to each other as the products of their bases by their altitudes. PROPOSITION IV. **The area of a rectangle is equal to the product of its** base and altitude. PROPOSITION V. The area of a parallelogram is equal to the product of its base and... | |
| Daniel Carhart - Surveying - 1888 - 498 pages
...sides, and s their sum, A= V««-a)« If the triangle is equilateral and s = length of a side, 50. **The Area of a Rectangle is equal to the product of its length and breadth,** or A = bl where b = breadth and I = length. 51. The Area of a Parallelogram is equal to the product... | |
| James Wallace MacDonald - Geometry - 1889 - 137 pages
...those of Newton and Leibnitz, is that it is true. Let us next take the following proposition : — **The area of a rectangle is equal to the product of its** base and altitude. This is first established in the case where the base and altitude are commensurable.... | |
| James Wallace Macdonald - Geometry - 1894 - 65 pages
...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured ? Proposition I. A Theorem. 236. **The area of a rectangle is equal to the product of its** base and altitude. CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable.... | |
| James Wallace MacDonald - Geometry - 1889 - 63 pages
...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured? Proposition I. A Theorem. 236. **The area of a rectangle is equal to the product of its** base and altitude. . CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable.... | |
| Edward Albert Bowser - Geometry - 1890 - 393 pages
...its altitude 39 inches. Reduce to the same unit, and compare. AnS. 4^-. Proposition 3. Theorem. 360. **The area of a rectangle is equal to the product of its** base and altitude. Hyp. Let R be the rectangle, b the base, and a the altitude expressed in numbers... | |
| Education - 1896
...that a line tangent to a circle is perpendicular to the radius drawn to the point of contact. 6. Prove **the area of a rectangle is equal to the product of its** base by its altitude. How would you prove the same for a parallelogram? 7. Problem: Given the hypotenuse... | |
| James Baldwin (Ph.D.) - Arithmetic - 1891 - 264 pages
...the square or the rectangle ? 5. Draw a triangle having half the area of the square. 6. Learn this : **The area of a rectangle is equal to the product of its length** multiplied by its width. 7. Draw a rectangle 3 in. wide and 5 in. long. Also a triangle 3 in. wide... | |
| Seth Thayer Stewart - Geometry - 1891 - 406 pages
...v., PROP. XIv.) Dividing both terms of the first couplet by 0 gives PROPOSITION XIII. 352. Theorem : **The area of a rectangle is equal to the product of its** base and altitude. Statement : Let R be any rectangle ; 6, its base ; and a, its altitude. The rectangle... | |
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