 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 370 pages
...Find the ratio of the areas of the two rectangles. 166 AREAS OF POLYGONS PROPOSITION III. THEOREM 339. The area of a rectangle is equal to the product of its base and altitude. R 1 u Hyp. R is a rectangle with base b and altitude a. To prove area of R = ax... | |
 | Alan Sanders - Geometry, Plane - 1901 - 247 pages
...the first rectangle is 20 sq. ft., as that has not yet been established.] PROPOSITION V. THEOREM 586. The area of a rectangle is equal to the product of its base and altitude. AD Let ABCD be any rectangle. To Prove ABCD = ax 6. Proof. Let the square U, each... | |
 | Metal-work - 1901
...found in this manner; hence, we have the following general statement: xJIJ. Area of 11 Kectiuigle. — The area of a rectangle is equal to the product of its base and altitude. This is called a general statement, because it is true for all rectangles. This... | |
 | Frank Joseph Schneck - Business mathematics - 1902 - 299 pages
...and three or more sides that are parallelograms, is a Prism. TRIANGULAR PRISM RECTANGULAR PRISM 212. The area of a rectangle is equal to the product of its length and breadth. 213. A rectangular prism that is one unit high has a volume equal to the product of its length and... | |
 | John Williston Cook, Nebraska C. Cropsey - Arithmetic - 1903 - 327 pages
...64. The number of square units in a rectangle is called its area. From the above it is evident that the area of a rectangle is equal to the product of its length and width. The length and width are called the two dimensions of the rectangle. 65. The area of a rectangle... | |
 | John Marvin Colaw - Algebra - 1903 - 432 pages
...equal to the subtrahend. 58. The product divided by the multiplier is equal to the multiplicand. 59. The area of a rectangle is equal to the product of its base by its altitude. 60. The area of a circle is equal to the square of its radius multiplied by w.... | |
 | Alan Sanders - Geometry - 1903 - 384 pages
...the first rectangle is 20 sq. ft., as that has not yet been established.] PROPOSITION V. THEOREM 586. The area of a rectangle is equal to the product of its base and altitude. BC D Let ABCD be any rectangle. To Prove ABCD = axb. Proof. Let the square U, each... | |
 | American School (Chicago, Ill.) - Engineering - 1903
...that is, B ~ tf Multiplying equations (1) and (2), we have A a X b B ~ a' x V THEOREM 1 XIII. 1 94. The area of a rectangle is equal to the product of its base and altitude. iL Let a and b be the numerical measures of the altitude and base of the rectangle... | |
 | Edward Leamington Nichols, William Suddards Franklin - Physics - 1904
...Arithmetrical or algebraic operations among physical quantities involve both units and measures. Thus the area of a rectangle is equal to the product of its length into its breadth, say 10 centimeters x 15 centimeters which is equal to 150 centimeters x centimeters... | |
 | George Albert Wentworth - Geometry - 1904 - 473 pages
...breadth. Compare their areas. and R a R' i a " S AREAS OF POLYGONS. PROPOSITION III. THEOREM. 398. The area of a rectangle is equal to the product of its base by its altitude. Let R be a rectangle, b its base, and a its altitude. To prove that the area... | |
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The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R. 
