## The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected; and Some of Euclid's Demonstrations are Restored. Also the Book of Euclid's Data, in Like Manner Corrected. the first six books, together with the eleventh and twelfth |

### From inside the book

Page 38

And , by the preceeding

to twice as many right angles as there are triangles , that is , as there are sides of

the figure ; and the fame angles are equal to the angles of the figure , together ...

And , by the preceeding

**proposition**, all Wthe angles of these triangles are equalto twice as many right angles as there are triangles , that is , as there are sides of

the figure ; and the fame angles are equal to the angles of the figure , together ...

Page 55

Wherefore , if a straight line , & c . Q. Ė . D. From this

the difference of the squares of two unequal lines AC , CD , is equal to the

rectangle contained by their sum and difference . D4 PRO P , Book II . PRO P. VI .

Wherefore , if a straight line , & c . Q. Ė . D. From this

**proposition**it is manifeft , thatthe difference of the squares of two unequal lines AC , CD , is equal to the

rectangle contained by their sum and difference . D4 PRO P , Book II . PRO P. VI .

Page 57

I. figure as in the preceeding

add to each of them CK ; the whole AK is b 43. 1 . therefore equal to the whole

CE ; therefore . AK , CE are double of A с AK : But AK , CE are the gnomon B AKF

...

I. figure as in the preceeding

**propositions**: And because AG is equal o to GE ,add to each of them CK ; the whole AK is b 43. 1 . therefore equal to the whole

CE ; therefore . AK , CE are double of A с AK : But AK , CE are the gnomon B AKF

...

Page 112

Let ABCDE be the given circle ; it is required to describe an equilateral and

equiangular pentagon about the circle ABCDE . Let the angles of a pentagon ,

inscribed in the circle , by the last

that ...

Let ABCDE be the given circle ; it is required to describe an equilateral and

equiangular pentagon about the circle ABCDE . Let the angles of a pentagon ,

inscribed in the circle , by the last

**proposition**, be in the points A , B , C , D , E , sothat ...

Page 134

M Let A , B have each of them the same ratio to C ; A is equal to B : For , if they

are not equal , one of them is greater than the other ; let A be the greater ; then ,

by what was fheon in the preceeding

of ...

M Let A , B have each of them the same ratio to C ; A is equal to B : For , if they

are not equal , one of them is greater than the other ; let A be the greater ; then ,

by what was fheon in the preceeding

**proposition**, there are some equimultiplesof ...

### What people are saying - Write a review

We haven't found any reviews in the usual places.

### Other editions - View all

### Common terms and phrases

added alſo altitude angle ABC angle BAC baſe becauſe Book Book XI caſe circle circle ABCD circumference common cone cylinder definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides firſt folid fore four fourth given angle given in poſition given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane produced prop proportionals propoſition pyramid radius rectangle rectangle contained remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC Take taken theſe third triangle ABC wherefore whole

### Popular passages

Page 32 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...

Page 165 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF.

Page 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Page 10 - When several angles are at one point B, any ' one of them is expressed by three letters, of which ' the letter that is at the vertex of the angle, that is, at ' the point in which the straight lines that contain the ' angle meet one another, is put between the other two ' letters, and one of these two is...

Page 55 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.

Page 32 - ... then shall the other sides be equal, each to each; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, BCA equal to the angles DEF, EFD, viz.

Page 45 - To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.

Page 211 - AB shall be at right angles to the plane CK. Let any plane DE pass through AB, and let CE be the common section of the planes DE, CK ; take any point F in CE, from which draw FG in the plane DE at right D angles to CE ; and because AB is , perpendicular to the plane CK, therefore it is also perpendicular to every straight line in that plane meeting it (3.

Page 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.

Page 304 - Thus, if B be the extremity of the line AB, or the common extremity of the two lines AB, KB, this extremity is called a point, and has no length : For if it have any, this length must either be part of the length of the line AB, or of the line KB.