 | Nathan Scholfield - Geometry - 1845 - 506 pages
...Therefore, -=^that is, sin. «=sin. (180° — «) an important proposition which enunciated in words, is, the sine of an angle is equal to the sine of its supplement. Again, cs=cs; CA~CA cos. t= — cos. (180° — d), 42 If, as in the annexed figure, we draw CP', making... | |
 | Nathan Scholfield - Conic sections - 1845 - 542 pages
...Therefore, -=^that is, sin. 6— sin. (180° — 6) an important proposition which enunciated in words, is, the sine of an angle is equal to the sine of its supplement. Again, CA~CA cos. 6= — cos. (180° — 6), that is, the cosine of an angle, and the cosine of its... | |
 | Thomas Grainger Hall - Trigonometry - 1848 - 192 pages
...draw PJ.M! I1 OB. , . ., .; sin. (тг—А) , .. cos. (тг - A ) PN = - = sm. -ON — cos. A ; or, the sine of an angle is equal to the sine of its supplement, and the cosine of an angle is equal to the cosine of its supplement, but with a negative sign. Hence,... | |
 | John Radford Young - Measurement - 1850 - 294 pages
...logarithms and without them. Ans. Diagonal 16-9 feet, and Area 102-53 Feet. * It is to be remembered that the sine of an angle is equal to the sine of its supplement (see page 50). In the present example, the opposite angles of the quadrilateral are supplements of... | |
 | Joseph Allen Galbraith - 1852 - 84 pages
...case, as it generally admits of two solutions. From equation (1) we obtain the value of log sin B, but as the sine of an angle is equal to the sine of its supplement (Chap. II. sect. 3), it follows that to the same numerical value of log sin B corresponds two angles... | |
 | Royal Military Academy, Woolwich - Mathematics - 1853 - 476 pages
...angle opposite to the less are given, we find the sine of the angle opposite to the greater side, and as the sine of an angle is equal to the sine of its supplement, there is no reason, without other considerations, to prefer the acute angle found by the tables to... | |
 | Charles Davies, William Guy Peck - Electronic book - 1855 - 592 pages
...the figure, which satisfy the conditions of the problem. The two solutions arise from the fact that the sine of an angle is equal to the sine of its supplement 20 CYCLOPEDIA OF MATHEMATICAL SCIENCE. 21 perpendicular Cd, there will be but one solu-f AM'PLI-TUDE.... | |
 | Thomas Kimber - Mathematics - 1865 - 302 pages
...sine of an angle was equal to the cosine of its complement, and vice versa. We will now prove that the sine of an angle is equal to the sine of its supplement, where by supplement is meant, the excess of two right angles over the angle in question. Observe in... | |
 | Alfred Challice Johnson - Plane trigonometry - 1865 - 166 pages
...I. Tan. 180° = ZÍÍ = - oo*. Sec. = &c. And so on for the other quadrants. 23. To prove that — The sine of an angle is equal to the sine of its supplement, and that The cosine of an angle is equal to the cosine of its supplement, but is of different sign.... | |
 | Joseph Allen Galbraith - Mathematics - 1866 - 132 pages
...is acute, it generally admits of two solutions. From equation (1), we obtain the value of log sin B; but as the sine of an angle is equal to the sine of its supplement (Chap. II., equation (24)), it follows that to the same tabular value of log sin B corresponds two... | |
| |
The sine of an angle is equal to the sine of its supplement. The sine rule Consider fig. 
