| Jeremiah Day - Measurement - 1831 - 394 pages
...the third side may be found, without the aid of the trigonometrical tables, by the proposition, that the square of the hypothenuse is equal to the sum of the squares of the two perpendicular sides. (Euc. 47. I.) If the legs be given, extracting the square root... | |
| Francis Lieber, Edward Wigglesworth - Encyclopedias and dictionaries - 1832 - 656 pages
...important : The three angles of a triangle are together equal to two right angles ; and in aright-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the two sides. This lust is still called the Pythagorean theorem (also magiater nuithtseos),... | |
| William Smyth - Plane trigonometry - 1834 - 94 pages
...third. This case, however, may be solved by means of the known property of a right angled triangle, viz. the square of the hypothenuse is equal to the sum of the squares of the two sides. It may moreover be resolved with facility by means of the two propositions... | |
| Abel Flint - Geometry - 1835 - 366 pages
...following PROPOSITION ; IN EVERY RIGHT ANGLED TRIANGLE, THE SQUARE OF THE HYPOTHENUSE IS EQUAL TO THE SUM OF THE SQUARES OF THE TWO LEGS. HENCE, THE SQUARE...THE HYPOTHENUSE, THE REMAINDER WILL BE THE SQUARE OP THE REQUIRED LEG. As in the preceding EXAMPLE; the square of the leg AB 40 is 1600 ; this subtracted... | |
| Abel Flint - Geometry - 1835 - 368 pages
...be found by the square root, without finding the angles ; according to the following PROPOSITION ; IN EVERY RIGHT ANGLED TRIANGLE, THE SQUARE OF THE HYPOTHENUSE IS EQUAL TO THE SUM OF THE SQUARES OF THE TWO LEGS. HENCE, THE SQUARE OF THE GIVEN LEG BEING SUBTRACTED FROM THE SQUARE OF THE... | |
| W. H. Spiller - Algebra - 1835 - 210 pages
...root, . 2x + 15 = ± 21 ; ,., = ! = , Ex 22. Here, we will suppose the hypothenuse to be x ; then, as the square of the hypothenuse is equal to the sum of the squares of the sides in a right-angled triangle, we shall have or *s = 2r!— 18* +45; transpo. and... | |
| Adrien Marie Legendre - Geometry - 1836 - 394 pages
...found by the first two theorems ; or if two of the sides are given, by means of the property, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. EXAMPLES. Ex. 1. In the right angled triangle BCA, there are given... | |
| Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...side fuund? 3. Kule for finding the hypothenuse, having the other two sides given ? Base. 9 2 AC=9=81 In every right angled triangle, the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
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