 | Benjamin Greenleaf - Geometry - 1861 - 638 pages
...units contained in the altitude. PROPOSITION V. — THEOREM. 225. The area of any parallelogram is equal to the product of its base by its altitude. Let ABCD be any parallelogram, FD AB its base, and BE its altitude ; then will its area be equal to the product... | |
 | Benjamin Greenleaf - Geometry - 1863 - 504 pages
...units contained in the altitude. PROPOSITION V. — THEOREM. 225. The area of any parallelogram is equal to the product of its base by its altitude. Let ABCD be any parallelogram, FDE AB its base, and BE its altitude ; then will its area be equal to the product... | |
 | Adrien Marie Legendre - Geometry - 1863 - 464 pages
...the rectangle AEGF will be the superficial unit, and we shall have, AB x AD ABCD = AB x AD : hence, the area of a rectangle is equal to the product of its base and altitude ; that is, the number of superficial units in the rectangle, is equal to the product... | |
 | Charles Davies - Mathematics - 1867 - 186 pages
...law of change, the second shall decrease according to the same law ; and the reverse. For example : the area of a rectangle ^ is equal to the product of its base and altitude. Then, in the rectangle ABCD, we have Area=AB x BO. Take a second rectangle EFGII,... | |
 | Benjamin Greenleaf - Geometry - 1868 - 340 pages
...imits contained in the altitude. PROPOSITION V. — THEOREM. 225. The area of any parallelogram is equal to the product of its base by its altitude. Let ABCD be any parallelogram, F DEC AB its base, and BE its altitude ; then will its area be equal to the product... | |
 | Edward Brooks - Geometry - 1868 - 284 pages
...other. It is one of the most interesting and practical books of Geometry. AREA OF POLYGONS. THEOREM I. The area of a rectangle is equal to the product of its base and altitude. Let ABCD be a rectangle; then will its area be equal to the product of its base... | |
 | Benjamin Greenleaf - 1869 - 516 pages
...units contained in the altitude. PROPOSITION V. — THEOREM. 226. The area of any parallelogram is equal to the product of its base by its altitude. Let ABCD be any parallelogram, FDEC AB its base, and BE its altitude ; then will its area be equal to the product... | |
 | John Reynell Morell - Geometry - 1871 - 156 pages
...an inch, a foot, &c. Plane figures that have equal superficial extension are called equivalent. 109. The area of a rectangle is equal to the product of its base by its height. This proposition is easily deduced from the simple inspection of Figure 89. The area of every... | |
 | Elias Loomis - Geometry - 1871 - 302 pages
...number of linear units contained in the altitude. PROPOSITION V. THEOREM. The area of a parallelogram is equal to the product of its base by its altitude. Let ABCD be a parallelogram, AF its altitude, and AB its base ; then is its surface measured by the product of AB... | |
 | William Chauvenet - Geometry - 1871 - 380 pages
...represent them when they are measured by the linear unit (III. 8). PROPOSITION III.— THEOREM. 7. The area of a rectangle is equal to the product of its base and altitude. Let R be any rectangle, If its base and h its altitude numerically expressed in... | |
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The area of a rectangle is equal to the product of its base and altitude. 
