 | William James Milne - Geometry, Modern - 1899 - 258 pages
...long and 7" wide ? How may the amount of surface, or the area of any rectangle, be found? . Theorem. The area of a rectangle is equal to the product of its base by its altitude. Data : Any rectangle, as A, whose base is d and altitude e. To prove area of A = dx e. Proof.... | |
 | George Albert Wentworth - Geometry - 1899 - 500 pages
...length of the rectangle is 4 times its breadth. Compare their areas. PROPOSITION III. THEOREM. 398. The area of a rectangle is equal to the product of its base by its altitude. R Let R be a rectangle, b its base, and a its altitude. To prove that the area of H = a X... | |
 | George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...length of the rectangle is 4 times its breadth. Compare their areas. PROPOSITION III. THEOBEM. 398. The area of a rectangle is equal to the product of its base by its altitude. R Let R be a rectangle, b its base, and a its altitude. To prove that the area of R = a X... | |
 | William James Milne - Geometry - 1899 - 398 pages
...8" long and 7" wide? How may the amount of surface, or the area of any rectangle, be found? Theorem. The area of a rectangle is equal to the product of its base by its altitude. Data : Any rectangle, as A, whose base is d and altitude e. Proof. Assume that the unit of... | |
 | George Albert Wentworth - Geometry, Solid - 1899 - 248 pages
...drawn, the tangent is the mean proportional between the whole secant and its external segment. 398. The area of a rectangle is equal to the product of its base by its altitude. 400. The area of a parallelogram is equal to the product of its base by its altitude. 403.... | |
 | Charles Austin Hobbs - Geometry, Plane - 1899 - 266 pages
...to 6 and an altitude equal to A. <S' 6 S—A ra R=AxB r ax b' QED 170 Proposition 164. Theorem. 200. The area of a rectangle is equal to the product of its base and altitudeULI Hypothesis. R is a rectangle whose base and altitude are B and A respectively.... | |
 | Harvard University - Geometry - 1899 - 39 pages
...of two rectangles are to each other as the products of their bases and their altitudes. Corollary. The area of a rectangle is equal to the product of its base and its altitude. THEOREM IV. The area of a parallelogram is equal to the product of its base... | |
 | Webster Wells - Geometry - 1899 - 450 pages
...M a ff a 165 304. The dimensions of a rectangle are its base and altitude. PROP. III. THEOREM. 305. The area of a rectangle is equal to the product of its base and altitude. Note. In all propositions relating to areas, the unit of surface (§ 302) is understood... | |
 | Edward Brooks - Geometry, Modern - 1901 - 278 pages
...factor S, We have R : R' = axb : a' X b'. II. 11. Therefore, etc. 150 PROPOSITION IV. — THEOREM. The area of a rectangle is equal to the product of its base by its altitude. Given. — Let R be a rectangle whose ba.se is b and altitude a. To Prove. — Then we are... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1902 - 394 pages
...Find the ratio of the areas of the two rectangles. 166 AREAS OF POLYGONS PROPOSITION III. THEOREM 339. The area of a rectangle is equal to the product of its base and altitude. R 1 u Hyp. R is a rectangle with base b and altitude a. To prove area of R = ax... | |
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The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R. 
