 | George Albert Wentworth - Arithmetic - 1886 - 392 pages
...rectangle equivalent to the square, but which cannot be made to coincide with it. FIG. 43. 417. THEOREM. The area of a rectangle is equal to the product of its base by its altitude (§ 160). 418. THEOREM. The area of a square, therefore, is equal to the square of the number... | |
 | Christian Brothers - Arithmetic - 1888 - 484 pages
...between 2809 sq. ft. Ï500 sy. ft., or У09 sg. it. 28'09 2500 50 3 502 = = 100 3 50x2 309 53 Ans. Since the area of a rectangle is equal to the product of its length and width, the width is equal to the area divided by the length. Therefore, the probable width... | |
 | William Chauvenet, William Elwood Byerly - Geometry - 1887 - 331 pages
...two rectangles are to each other as the products of their bases by their altitudes. PROPOSITION IV. The area of a rectangle is equal to the product of its base and altitude. PROPOSITION V. The area of a parallelogram is equal to the product of its base and... | |
 | Daniel Carhart - Surveying - 1888 - 536 pages
...sides, and s their sum, A= V««-a)« If the triangle is equilateral and s = length of a side, 50. The Area of a Rectangle is equal to the product of its length and breadth, or A = bl where b = breadth and I = length. 51. The Area of a Parallelogram is... | |
 | James Wallace MacDonald - Geometry - 1894 - 76 pages
...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured ? Proposition I. A Theorem. 236. The area of a rectangle is equal to the product of its base and altitude. CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable.... | |
 | James Wallace MacDonald - Geometry - 1889 - 80 pages
...OF RECTILINEAR FIGURES. I. AREA. 235. What is area? a. How measured? Proposition I. A Theorem. 236. The area of a rectangle is equal to the product of its base and altitude. . CASE I. When the base and altitude are commensurable. CASE II. When they are incommensurable.... | |
 | James Wallace MacDonald - Geometry - 1889 - 158 pages
...those of Newton and Leibnitz, is that it is true. Let us next take the following proposition : — The area of a rectangle is equal to the product of its base and altitude. This is first established in the case where the base and altitude are commensurable.... | |
 | Education - 1896 - 446 pages
...that a line tangent to a circle is perpendicular to the radius drawn to the point of contact. 6. Prove the area of a rectangle is equal to the product of its base by its altitude. How would you prove the same for a parallelogram? 7. Problem: Given the hypotenuse and one... | |
 | Edward Albert Bowser - Geometry - 1890 - 420 pages
...its altitude 39 inches. Reduce to the same unit, and compare. AnS. 4^-. Proposition 3. Theorem. 360. The area of a rectangle is equal to the product of its base and altitude. Hyp. Let R be the rectangle, b the base, and a the altitude expressed in numbers... | |
 | James Baldwin - Arithmetic - 1891 - 278 pages
...the square or the rectangle ? 5. Draw a triangle having half the area of the square. 6. Learn this : The area of a rectangle is equal to the product of its length multiplied by its width. 7. Draw a rectangle 3 in. wide and 5 in. long. Also a triangle 3 in.... | |
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The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R. 
