| Education - 1911
...in a circumference is measured by one-half the arc Intercepted by its sides. 3. Two triangles having **an angle of one equal to an angle of the other are to each other** as the products of the sides including the equal angles. 4. Given a parallelogram and a point outside... | |
| David Eugene Smith - Geometry - 1911 - 339 pages
...with the tape, is given on page 99. THEOREM. The areas of two triangles which have an angle of the **one equal to an angle of the other are to each other** as the products of the sides including the equal angles. This proposition may be omitted as far as... | |
| Geometry, Plane - 1911 - 178 pages
...vertices of a parallelogram. When will this parallelogram be a rectangle? 2. Prove that if two triangles **have an angle of one equal to an angle of the other,** and the sides including these angles proportional, the triangles are similar. Prove that if two diagonals... | |
| Clara Avis Hart, Daniel D. Feldman, Virgil Snyder - Geometry, Solid - 1912 - 188 pages
...circle is equal to one half its perimeter multiplied by the radiue of the inscribed circle. 498. Two **triangles which have an angle of one equal to an angle of the other are to each other** as the products of the sides including the equal angles. 503. Two similar triangles are to each other... | |
| William Betz, Harrison Emmett Webb, Percey Franklyn Smith - Geometry, Plane - 1912 - 332 pages
...measurements being in centimeters. f? . J/r IJ t T' y, d ' i d PROPOSITION IV. THEOREM 337. If two triangles **have an angle of one equal to an angle of the other,** their areas are to each other as the products of the sides including the equal angles. c' zc Given... | |
| William Betz, Harrison Emmett Webb, Percey Franklyn Smith - Geometry, Plane - 1912 - 332 pages
...44, 36, 28, and 20, measurements being in centimeters. PROPOSITION IV. THEOREM 337. If two triangles **have an angle of one equal to an angle of the other,** their areas are to each other as the products of the sides including the equal angles. Given two triangles... | |
| Clara Avis Hart, Daniel D. Feldman - Geometry - 1912 - 488 pages
...of two given circles. Ex. 1125. Assuming that the areas of two triangles which have an angle of the **one equal to an angle of the other are to each other** as the products of the sides including the equal angles, prove that the bisector of an angle of a triangle... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 457 pages
...PLANE GEOMETRY PROPOSITION XIII. THEOREM 378. The areas of two triangles which have an angle of the **one equal to an angle of the other are to each other** as the products of the sides including the equal angles. Given A ABC and A'B'C', ZA = Z A'. To prove... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry, Plane - 1913 - 304 pages
...the student.] PROPOSITION XIII. THEOREM 378. The areas of two triangles which have an angle of the **one equal to an angle of the other are to each other** as the product of the sides including the equal angles. Given A ABC and A'B'C', Z A = ZA ' . To prove... | |
| George Albert Wentworth, David Eugene Smith - Geometry - 1913 - 470 pages
...ft, 9 ft., 5 ft. PROPOSITION VII. THEOREM 332. The areas of two triangles that have an angle of the **one equal to an angle of the other are to each other** as the products of the sides including the equal angles. •A. DB Given the triangles ABC and ADE,... | |
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