 | George Albert Wentworth - Geometry - 1904 - 496 pages
...breadth. Compare their areas. and R a R' i a " S AREAS OF POLYGONS. PROPOSITION III. THEOREM. 398. The area of a rectangle is equal to the product of its base by its altitude. Let R be a rectangle, b its base, and a its altitude. To prove that the area... | |
 | Fletcher Durell - Geometry, Solid - 1904 - 232 pages
...to twice the product of the given side by the projection of the median upon that side. BOOK IV. 383. The area of a rectangle is equal to the product of its base by its altitude. 385. The area of a parallelogram is equal to the product of its base by its altitude.... | |
 | Fletcher Durell - Geometry, Plane - 1904 - 382 pages
...dimensions are 9X2 in. B a R' 1 S b b' 6 AREAS OP POLYGONS AREAS OF POLYGONS PROPOSITION III. THEOREM 383. The area of a rectangle is equal to the product of its base by its altitude. 1\U\ 1 Given the rectangle R, with a base containing 6, and an. altitude containing... | |
 | Fletcher Durell - Geometry - 1911 - 553 pages
...that of one whose dimensions are 9 X 2 in. R a R " 5 i AREAS OF POLYGONS PROPOSITION III. THEOREM 383, The area of a rectangle is equal to the product of its base by its altitude. Given the rectangle R, with a base containing b, and an altitude containing h... | |
 | Walter Burton Ford, Charles Ammerman - Geometry, Solid - 1913 - 184 pages
...called its dimensions. In Chapter IV (§ 181), we assumed (without proof) the well-known principle that the area of a rectangle is equal to the product of its two dimensions. Similarly, we shall now assume that the volume of a rectangular parallelepiped" is... | |
 | William Benjamin Fite - Algebra - 1913 - 368 pages
...m2»3 + 5 mn* + и5. 51. Multiplication of Polynomials. — The student is familiar with the fact that the area of a rectangle is equal to the product of its base and altitude. If we have two rectangles with the common altitude a and bases x and y respectively,... | |
 | William Benjamin Fite - Algebra - 1913 - 304 pages
...mW + 5 mw4 + w5. 51. Multiplication of Polynomials. — The student is familiar with the fact that the area of a rectangle is equal to the product of its base and altitude. If we have two rectangles with the common altitude a and bases x and y respectively,... | |
 | Arthur Schultze, Frank Louis Sevenoak - Geometry - 1913 - 490 pages
...of its sides 20 in. Find the ratio of the areas of the two rectangles. PROPOSITION III. THEOREM 347. The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove B = a x b. Proof. Let U... | |
 | Walter Burton Ford, Charles Ammerman - Geometry, Plane - 1913 - 376 pages
...called its dimensions. In Chapter IV (§ 181), we assumed (without proof) the well-known principle that the area of a rectangle is equal to the product of its two dimensions. Similarly, we shall now assume that the volume of a rectangular parallelepiped is equal... | |
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The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R. 
