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" The area of a rectangle is equal to the product of its base and altitude. Given R a rectangle with base b and altitude a. To prove R = a X b. Proof. Let U be the unit of surface. .R axb U' Then 1x1 But - is the area of R. "
A Treatise on Mensuration, Both in Theory and Practice - Page 91
by Charles Hutton - 1788 - 703 pages
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Plane Geometry

William James Milne - Geometry, Plane - 1899 - 242 pages
...long and 7" wide ? How may the amount of surface, or the area of any rectangle, be found? . Theorem. The area of a rectangle is equal to the product of its base by its altitude. Data : Any rectangle, as A, whose base is d and altitude e. To prove area of...
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SYLLABUS OF PROPOSITIONS IN GEOMETRY

1899
...of two rectangles are to each other as the products of their bases and their altitudes. Corollary. The area of a rectangle is equal to the product of its base and its altitude. THEOREM IV. The area of a parallelogram is equal to the product of its base...
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Plane and Solid Geometry

William James Milne - Geometry - 1899 - 384 pages
...8" long and 7" wide? How may the amount of surface, or the area of any rectangle, be found? Theorem. The area of a rectangle is equal to the product of its base by its altitude. Data : Any rectangle, as A, whose base is d and altitude e. Proof. Assume that...
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Plane and Solid Geometry

George Albert Wentworth - Geometry - 1899 - 473 pages
...length of the rectangle is 4 times its breadth. Compare their areas. PROPOSITION III. THEOREM. 398. The area of a rectangle is equal to the product of its base by its altitude. R Let R be a rectangle, b its base, and a its altitude. To prove that the area...
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The Essentials of Geometry

Webster Wells - Geometry - 1899 - 395 pages
...M a ff a 165 304. The dimensions of a rectangle are its base and altitude. PROP. III. THEOREM. 305. The area of a rectangle is equal to the product of its base and altitude. Note. In all propositions relating to areas, the unit of surface ( 302) is understood...
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Plane and Solid Geometry

Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 370 pages
...Find the ratio of the areas of the two rectangles. AREAS OF POLYGONS PROPOSITION III. THEOKEM 339. The area of a rectangle is equal to the product of its base and altitude. 1 u Hyp. R is a rectangle with base b and altitude a. To prove area of R = ax b....
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Elementary Geometry, Plane and Solid: For Use in High Schools and Academies

Thomas Franklin Holgate - Geometry - 1901 - 440 pages
...other words, P contains the unit area bh times, or the measure of P is bh. THEOREM. The measure of the area of a rectangle is equal to the product of its base and its altitude. Or, more briefly, the area of a rectangle is equal to the product of its base...
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Graded Work in Arithmetic: Years, 5-8, Volume 5

Samuel Wesley Baird - Arithmetic - 1901 - 160 pages
...retaining the same base and altitude. Rhomboid Area=6 sq. in. 3 in. 3in. s Area = 6 sq. in. 3in. As the area of a rectangle is equal to the product of its base and altitude, this is also the area of the rhomboid. PRACTICAL MENSUKATION 125 LESSON 111 1. What...
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Plane Geometry

Arthur Schultze - 1901
...its sides 20 inches. Find the ratio of the areas of the two rectangles. PROPOSITION III. THEOREM 339. The area of a rectangle is equal to the product of its base and altitude. R 1 u Hyp. R is a rectangle with base 6 and altitude a, To prove area of R = ax...
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Plane Geometry

Edward Brooks - Geometry, Plane - 1901 - 266 pages
...factor S, We have R : R' = axb : a' X b'. II. 11. Therefore, etc. 150 PROPOSITION IV. — THEOREM. The area of a rectangle is equal to the product of its base by its altitude. Given. — Let R be a rectangle whose ba.se is b and altitude a. To Prove. —...
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