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" Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides. "
The Elements of Euclid; viz. the first six books, together with the eleventh ... - Page 30
by Euclides - 1814
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Examination papers, and division lists, &c. [afterw.] General certificate of ...

Oxford univ, local exams - 1880
...circle, and by a straight line placed in a circle. 2. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. 3. If the square described on one side of a triangle be equal to the squares described on the other...
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An elementary treatise on geometrical drawing

John Henry Robson - 1880
...Book. 12. By Euc. I. 32, Cor. 1, it is proved that " All the Interior angles of any Rectilineal figure, "together with four right angles, are equal to "twice as many right angles as the figure has " sides." If, therefore, we suppose the polygon to have n sides, All its interior angles + 4.90 .= 272.90 . -....
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(Report).

Elizabethan club - 1880
...at the other point, and similarly of the obtuse angles. 3. All the angles of a rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. A floor has to be laid with tiles in the form of regular figures all equal and similar ; show what...
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The Elements of Euclid for the Use of Schools and Colleges: With Notes, an ...

Isaac Todhunter - Euclid's Elements - 1880 - 400 pages
...if a side of any triangle &c. <JEĽ. COROLLARY 1. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has side*. For any rectilineal figure ABCDE can be divided into as many triangles as the figure has sides,...
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Elements of Geometry, Conic Sections, and Plane Trigonometry

Elias Loomis - Geometry - 1880 - 443 pages
...is the complement of the other. PROPOSITION XXVIII. THEOREM. All the interior angles of a polygon, together with four right angles, are equal to twice as many right angles as the figure IMS sides. Let ABCDE be any polygon ; then all its interior angles A, B, C, D, E, together with four...
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An Elementary Geometry: Plane, Solid and Spherical

William Frothingham Bradbury - Geometry - 1880 - 240 pages
...minus two. Let ABCDEF be the given polygon ; the sum of all the interior angles A, B, C, D, E, F, is equal to twice as many right angles as the figure has sides minus two. For if from any vertex A, diagonals AC, AD, AE, are drawn, the polygon will be divided into...
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A Treatise on Land-surveying: Comprising the Theory Developed from Five ...

William Mitchell Gillespie - Surveying - 1880 - 524 pages
...proposition of Geometry, that in any figure bounded by straight lines, the sum of all the interior angles is equal to twice as many right angles, as the figure has sides less two ; since the figure can be divided into that number of triangles. Hence this common rule. "...
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The Elements of geometry; or, The first six books, with the eleventh and ...

Euclides - 1881
...equal to twico as mauy right angles as the figure has sides. Therefore all the angles of the figure together with four right angles are equal to twice...All the exterior angles of any rectilineal figure, made by producing the sides successively in the same direction, are together equal to four right angles....
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The practical surveyor

Thomas Holloway (surveyor.) - 1881
...right angles or three hundred and sixty degrees. 3. All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides. Although further systems of proof could easily be quoted, I consider the foregoing quite sufficient...
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Practical Geometry for Second Grade Art-pupils and Private Schools

Thomas Newton Andrews - Geometry - 1881 - 160 pages
...Euclid, Book I., Prop, xxxi11., it is proved that "All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides." If we have to describe a pentagon on the base AB, we must first calculate the angles at the base. Thus...
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