 FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of...  Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books - Page 183by Euclid - 1765 - 464 pagesFull view - About this book
 | Euclid, John Playfair - Euclid's Elements - 1846 - 334 pages
...perpendicular FH is equal to the perpendicular FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK ; therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
 | Royal Military Academy, Woolwich - Mathematics - 1853 - 400 pages
...perpendicular FH is equal to the perpendicular FK : In the same manner it may be demonstrated that FL, FM, FG are each of them equal to FH, or FK ; Therefore the five straight lines FG, FH, FK, FL, FM are equal to one another ; wherefore the circle described from the... | |
 | Euclides - Geometry - 1853 - 176 pages
...perpendicular fh is equal to the perpendicular f k. In the same manner, it may be demonstrated that ft fm, fg are each of them equal to fh, or fk : therefore the five straight lines fg, fh, f fc f 1, fm are equal to one another : wherefore the circle described from... | |
 | Euclides - 1853 - 146 pages
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that 8. FL, FM, FG, are each of them equal to FH or FK: therefore 9. The five straight lines FG, FH, FK, FL, FM, are equal to one another; wherefore the circle described... | |
 | Euclides - 1855 - 270 pages
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may be shown that FL, FM, and FG, are each of them equal to FH, or FK. Therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre... | |
 | Robert Potts - Geometry, Plane - 1860 - 380 pages
...perpendicular FH is equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the... | |
 | Euclides - 1860 - 288 pages
...perpendicular FH is equal to the perpendicular FK. In the same manner, it may be demonstrated that FL, FM, and FG are each of them equal to FH or FK ; therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another ; wherefore the circle described from... | |
 | Euclides - 1862 - 172 pages
...perpendicular FH is equal to the perpendicular FK. In the same manner it may be demonstrated that FL, FM, FG, are each of them equal to FH or FK ; therefore the five straight linos FG, FH, FK, FL, FM, are equal to one another ; wherefore the circle described from the... | |
 | Euclides - 1863 - 122 pages
...triangles are equal (I. 26), and FH is equal to FK. In the same manner, it may shown that FL, FM, and FG are each of them equal to FH, or FK. Therefore the five straight lines FG, FH, FK, FL, and FM are equal to one another, and the circle described from the centre... | |
 | Euclides - 1864 - 448 pages
...perpendicular FHis equal to the perpendicular FK: in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK: therefore the five straight lines FG, FH, FK, FL, FMaie equal to one another : wherefore the circle described from the... | |
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