 | Francis Lieber, Edward Wigglesworth - Encyclopedias and dictionaries - 1832 - 656 pages
...important : The three angles of a triangle are together equal to two right angles ; and in aright-angled triangle, the square of the hypothenuse is equal to the sum of the squares of the two sides. This lust is still called the Pythagorean theorem (also magiater nuithtseos),... | |
 | William Smyth - Plane trigonometry - 1834 - 94 pages
...third. This case, however, may be solved by means of the known property of a right angled triangle, viz. the square of the hypothenuse is equal to the sum of the squares of the two sides. It may moreover be resolved with facility by means of the two propositions... | |
 | W. H. Spiller - Algebra - 1835 - 210 pages
...root, . 2x + 15 = ± 21 ; ,., = ! = , Ex 22. Here, we will suppose the hypothenuse to be x ; then, as the square of the hypothenuse is equal to the sum of the squares of the sides in a right-angled triangle, we shall have or *s = 2r!— 18* +45; transpo. and... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...found by the first two theorems ; or if two of the sides are given, by means of the property, that the square of the hypothenuse is equal to the sum of the squares of the other two sides. EXAMPLES. Ex. 1. In the right angled triangle BCA, there are given... | |
 | Charles Guilford Burnham - Arithmetic - 1837 - 266 pages
...side fuund? 3. Kule for finding the hypothenuse, having the other two sides given ? Base. 9 2 AC=9=81 In every right angled triangle, the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular ; therefore, the square root of the sum of the squares of the... | |
 | Charles Davies - Navigation - 1837 - 342 pages
...by either of the four last cases : or, if two of the sides are given, by means of the property that the square of the hypothenuse is equal to the sum of the squares of the other two sides. Or the parts may be found by Theorem V. EXAMPLES. 1. In a right-angled... | |
 | Alexander Jamieson - Fluid mechanics - 1837 - 516 pages
...sides DH and CE ; that is, tf=\(xy). Consequently, by the property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the base and perpendicular, we shall have (i,y =*• + «*—y)'; and by extracting the... | |
 | Madras literary society - 1837 - 996 pages
...which AE is the other kg, and AB, is the third side, or hypothenuse. Then, as in right angle triangles, the square of the hypothenuse is equal to the sum of the squares of the other two sides; in the right angle triangle AEB,— BE8 -f- AE JL AB* : but as BE,... | |
 | Charles William Hackley - Trigonometry - 1838 - 338 pages
...and a very simple formula depending upon the well known property of the right angled triangle, that the square of the hypothenuse is equal to the sum of the squares of the other two sides, a formula expressing the value of the sine of half an arc in terms... | |
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The square of the hypothenuse is equal to the sum of the squares of the other two sides ; as, 5033 402+302. 
