| GEORGE BRUCE HALSTED - 1885
...equal.) therefore, by 491, GH = BH'. In the same way HF = H'F', THEOREM VII. 511. Two triangles having **one angle of the one equal to one angle of the other, and** the sides about these angles proportional, are similar. HYPOTHESIS. £ B = £ G, and AB : BC : : FG... | |
| George Bruce Halsted - Geometry - 1886 - 366 pages
...equal.) therefore, by 491, GH = BH'. In the same way HF = H'F', THEOREM VII. 511. Two triangles having **one angle of the one equal to one angle of the other, and** the sides about these angles proportional, are similar. HYPOTHESIS. £ B = $. G, and AB : BC : : FG... | |
| New Brunswick. Board of Education - Education - 1889
...and those which are opposite to the equal angles are homologous sides. 6. Equal parallelograms which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional. N. В.- --Female candidates will... | |
| E. J. Brooksmith - Mathematics - 1889
...are the middle points ofAB, CD, prove that PQ_ is parallel to AC and BD. 10. Equal triangles, which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional ; and, conversely, triangles which... | |
| Eldred John Brooksmith, Robert Moir Milne - 1890 - 132 pages
...the line joining two alternate vertices of a given length. 7. Prove that equal parallelograms, which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional. 8. In a right-angled triangle, show... | |
| Edward Mann Langley, W. Seys Phillips - 1890 - 515 pages
...parallelograms as in VI. 23, ||gm AC : ||gm CF :: rect. BC, CD : rect. EC, CG. Ex. 717. — Triangles which **have one angle of the one equal to one angle of the other** are to one another in the ratio compounded of the ratios of the sides containing the equal angles.... | |
| Euclid - Geometry - 1890 - 400 pages
....-. a AC = a BF. (/3) is true. EUCLID Proposition 15. THEOREMS — (a) Triangles of equal area which **have one angle of the one equal to one angle of the other,** have their sides about the equal angles reciprocally proportional : (/3) and conversely, if two triangles... | |
| Queensland. Department of Public Instruction - Education - 1890
...segments of the base. What is the corresponding proposition for the external bisector ? 8. Triangles which **have one angle of the one equal to one angle of the other,** have to one another the ratio which is compounded of the ratios of the sides about the equal angles.... | |
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