 | Mathematics - 1836 - 488 pages
...base, shall be greater than the angle contained by the sides of the other. XXVI. If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, viz. either the sides adjacent to the equal angles, or the sides opposite... | |
 | John Playfair - Geometry - 1836 - 148 pages
...by BD, and that the right angle BED is equal to the right angle BFD, the two Iriangles EBD, FBD have two angles of the one equal to two angles of the other, and the side BD, which is opposite to one of the equal angles in each, is common to both ; therefore... | |
 | Charles Reiner - Geometry - 1837 - 246 pages
...and be equal to it. M. — Here, then, is a third instance of equality in triangles : what is it ? angles of the one equal to two angles of the other, each to each, and have likewise the sides adjacent to the equal angles equal to each other. M. — Repeat, now, all you... | |
 | Charles Reiner - Geometry - 1837 - 254 pages
...angles of the one is equal to the sum of the remaining two angles of the other. 2. If two triangles have two angles of the one equal to two angles of the other, each to each, the third angle of the one is equal to the third angle of the other ; that is, the triangles are equiangular.... | |
 | Euclid, James Thomson - Geometry - 1837 - 410 pages
...&c., are all equal. Hence (I. 6.) CH is equal to HD, DK to KE, &c. Also, in the triangles CHD, DKE, there are two angles of the one equal to two angles of the other, and (hyp.) the sides CD, DE, are equal : therefore (I. 26.) the sides CH, HD are equal to DK, KE, each... | |
 | A. Bell - Conic sections - 1837 - 180 pages
...Def. 7)i and therefore the angles AFG, AEG, are also equal. The triangles AGE, AGF, have therefore two angles of the one equal to two angles of the other, and they have also the side AG common ; wherefore they are equal, and the side AF is equal to the side... | |
 | William Whewell - 1837 - 226 pages
...therefore MLN is equal to LKH; and the angles at H and at N are right angles. Therefore the triangles have two angles of the one equal to two angles of the other ; and the side KL is equal to LM. Therefore the triangles are equal, and HL is equal to MN; that is,... | |
 | Euclides - Euclid's Elements - 1837 - 112 pages
...be > Z EOF. PROPOSITION XXVI. (Argument ad absurdum). Theorem. If two triangles have two angles of one equal to two angles of the other, each to each, and one side equal to one side; viz., either the sides adjacent to the equal angles, or opposite to the... | |
 | Andrew Bell - Euclid's Elements - 1837 - 290 pages
...the angles GMK, GMN, are both right angles by construction ; wherefore the triangles GMK, GMN, have two angles of the one equal to two angles of the other, and they have also the side GM common ; therefore they arc equal, and the side KM is equal to the side... | |
 | Euclides - 1838 - 264 pages
...angle EDF. Wherefore, if two triangles, &c. Q. t, n. PROP. XXVI. THEOR. °V'.' If two triangles have two angles of the one equal to two angles of the other, each to each ; and one side equal to one side, vis. either the sides adjacent to the equal angles, or the sides opposite... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. 
