| Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Abfe 1. If the first... | |
| Thomas Tucker Smiley - 1830 - 180 pages
...second terms to She same denomination, and to the lowest denomination mentioned in either of them. 3. **Multiply the second and third terms together, and divide the product by the .first term** ; the result will be the fourth term, or answer, in the same denomination to which the third term was... | |
| Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Daniel Adams - Arithmetic - 1830 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination M the third term. Note 1. If the first... | |
| Arithmetic - 1831 - 198 pages
...are; and if the third term consist of several denominations, reduce it to its lowest denomination; **then, Multiply the second and third terms together, and divide the product by the first term:** the quotient will be the answer. Note. — The product of the second and third termsis of the same... | |
| Thomas Conkling (W.) - Arithmetic - 1831 - 275 pages
...before taught; then, state the question as directed in whole numbers, p. 109; and, as in that rule, **multiply the second and third terms together, and divide the product by the first;** that is, multiply the denominator of the first term by the numerators of the 2d and 3d, for a new numerator;... | |
| Daniel Adams - Arithmetic - 1831 - 264 pages
...the two remaining numbers for the second term, and the greater for the first ; and, in either case, **multiply the second and third terms together, and divide the product by the first** for the answer, which will always be of the same denomination cs the third term. Note 1. If the first... | |
| William Ruger - Arithmetic - 1832 - 263 pages
...Prepare the given terms, as in Multiplication, and state the question the same as in whole numbers; **then multiply the second and third terms together and divide the product by the first:** Or, invert the first term, and multiply the three together, as in Multiplication ; the last product... | |
| |