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" Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer. "
The Theory and Practice of Surveying: Containing All the Instructions ...
by Robert Gibson - 1811 - 508 pages
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A Treatise of Practical Arithmetic

Robert Patterson - Arithmetic - 1819 - 156 pages
...we have the equation ad = be, and this divided by a, will give d = —. In words — multiply the a second and third terms together, and divide the product by the first, and the quotient will be the fourth, or term required. II. IN ALLIGATION ALTERNATE. Let a, A, = the...
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The Scholar's Arithmetic: Designed for the Use of Schools in the United States

Jacob Willetts - Arithmetic - 1822 - 191 pages
...DIRECT PROPORTION. RULE. Prepare the given terms, if necessary, and state them as ia whole numbers : multiply the second and third terms together, and divide the product by the first : Or, Invert the first term and multiply the three together, as in Multiplication. EXAMPLES. i . If...
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The American Tutor's Assistant Revised, Or, A Compendious System of ...

Zachariah Jess - Arithmetic - 1824 - 210 pages
...dols. ' A " 5 ' 3 : 6 :: 9 : 1 8 more requiring more I 20 : 40 :: 3 : 10 less requiring less RULE. Multiply the second and third terms together, and divide the product by the first ; the quotient will be the fourth term, or answer ; in the same name with the second. PROOF. Invert...
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The Teachers' Assistant: Or a System of Practical Arithmetic

Stephen Pike - Arithmetic - 1824 - 198 pages
...THREE, IN VULGAR FRACTIONS. Prepare the given terms, if necessary, and state them as in whole numbers ; multiply the second and third terms together, and divide the product by the first. Or, Invert the dividing term, and multiply the three terms together, as in Multiplication. EXAMPLES....
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The New Federal Calculator, Or, Scholar's Assistant: Containing the Most ...

Thomas Tucker Smiley - Arithmetic - 1825 - 180 pages
...second terms to the same denomination, and to the lowest denomination mentioned in either oi them. 3. Multiply the second and third terms together, and divide the product by the first term; the result will be-tbe fourth term OF answer in the same denomination to which the third term was reduced....
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Pike's System of Arithmetick Abridged: Designed to Facilitate the Study of ...

Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 200 pages
...kind, the first term ; and that which is of the same name or kind with the answer, the second term. 2. Multiply the second and third terms together, and...product by the first term, and the quotient will be the fourth term, or answer. The notes under the general rule are applicable to this rule. EXAMPLES. 1....
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Syllabus of Philosophical Lectures, Given During Each Half Year: At Poplar ...

Poplar House Academy - 1826 - 92 pages
...when necessary, to the same denomination, and the third to the lowest denomination mentioned in it. Then, multiply the second and third terms together, and divide the product by the first, and the quotient will be the answer, in the same denomination that the third term was reduced to ;...
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The Youth's Assistant in Theoretick and Practical Arithmetic

Zadock Thompson - Arithmetic - 1826 - 164 pages
...the same kind, the first term, and that which is of the same kind as the answer, the second term. 2.f Multiply the second and third terms together, and divide the product by the first, the quotient will be the answer. EXAMPLE. — If 8lb. of sugar cost $1.00, what will 401b-. of sugar...
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The Improved Arithmetic: Newly Arranged and Clearly Illustrated, Both ...

Daniel Parker - Arithmetic - 1828 - 348 pages
...terms. 4. If the third be composed of several denominations, reduce it to the lowest one named. 5. Then multiply the second and third terms together, and divide the product by the first, and the quotient will be the fourth term, or the answer sought ; and it will also be of the same denomination...
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Adams's New Arithmetic: Arithmetic, in which the Principles of Operating by ...

Daniel Adams - Arithmetic - 1828 - 264 pages
...the two remaining numbers for the second term, and the greater for the first; and, in either case, multiply the second and third terms together, and divide the product by the first for the answer, whieh will always be of the same denomination as the third term. Note 1. If the first...
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