Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books |
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Page 173
... equiangular to the given triangle DEF . Produce EF [ by 2. poft . ] both ways to the points H and G , and [ by 1. 3 ... equiangular to the triangle DEF , and [ by 4. def . 4. ] it is circum- fcribed about the circle A B C. Therefore a ...
... equiangular to the given triangle DEF . Produce EF [ by 2. poft . ] both ways to the points H and G , and [ by 1. 3 ... equiangular to the triangle DEF , and [ by 4. def . 4. ] it is circum- fcribed about the circle A B C. Therefore a ...
Page 180
... equiangular pentagon in a given circle c . Let the given circle be ABCDE . It is required to in- scribe an equilateral and equiangular pentagon in the circle ABCDE . Let Let [ by 10.4 . ] F G H be 180 Euclid's Elements . Book IV .
... equiangular pentagon in a given circle c . Let the given circle be ABCDE . It is required to in- scribe an equilateral and equiangular pentagon in the circle ABCDE . Let Let [ by 10.4 . ] F G H be 180 Euclid's Elements . Book IV .
Page 181
... equiangular to the triangle F G H ; fo that the angle C A D is equal to the angle F , the angles ACD , F G H B CDA equal to either cf the angles at G , H. Then either of the angles A CD , E CDA is double to the an- gle CAD . Now [ by 9 ...
... equiangular to the triangle F G H ; fo that the angle C A D is equal to the angle F , the angles ACD , F G H B CDA equal to either cf the angles at G , H. Then either of the angles A CD , E CDA is double to the an- gle CAD . Now [ by 9 ...
Page 182
... equiangular penta- gon about a given circle . Let the given circle be A B C D E. It is required to cir- cumfcribe an equilateral and equiangular pentagon about the circle A B C D E. Let the points of the angles of a pentagon infcribed ...
... equiangular penta- gon about a given circle . Let the given circle be A B C D E. It is required to cir- cumfcribe an equilateral and equiangular pentagon about the circle A B C D E. Let the points of the angles of a pentagon infcribed ...
Page 183
... GML are each equal to the angles H KL , KLM : Therefore the five angles G H K , HK L , KLM , L MG , MGH are equal to one another . Wherefore the N 4 KL . pen- pentagon G H K L M is equiangular . But Book IV . 183 Euclid's Elements .
... GML are each equal to the angles H KL , KLM : Therefore the five angles G H K , HK L , KLM , L MG , MGH are equal to one another . Wherefore the N 4 KL . pen- pentagon G H K L M is equiangular . But Book IV . 183 Euclid's Elements .
Other editions - View all
Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books Euclid,David Gregory No preview available - 2023 |
Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books Euclid,David Gregory No preview available - 2023 |
Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books Euclid,David Gregory No preview available - 2016 |
Common terms and phrases
A B C D alfo alſo angle ABC becauſe the angle bifected centre circle A B C circumference cone confequent cylinder defcribed demonftrated diameter equal angles equiangular equimultiples Euclid EUCLID's ELEMENTS fame altitude fame multiple fame ratio fame reafon fecond fegment femidiameter fhall fides A B fimilar fince firft firſt fixth folid angle folid parallelepipedon fome fphere ftand given circle given right line given triangle greater infcribed interfect join leffer lefs leſs parallel parallelogram perpendicular polygon prifm PROP propofition proportional pyramid rectangle contained regular polygon remaining angle right angles right line A B right lined figure right-lined SCHOLIUM ſquare thefe THEOR theſe thofe thoſe trapezium triangle ABC twice the fquare vertex the point Wherefore whofe bafe whoſe baſe
Popular passages
Page 247 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 30 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Page 248 - But it was proved that the angle AGB is equal to the angle at F ; therefore the angle at F is greater than a right angle : But by the hypothesis, it is less than a right angle ; which is absurd.
Page 18 - When a straight line set up on a straight line makes the adjacent angles equal to one another, each of the equal angles is right, and the straight line standing on the other is called a perpendicular to that on which it stands.
Page 32 - Let the straight line EF, which falls upon the two straight lines AB, CD, make the alternate angles AEF, EFD equal to one another; AB is parallel to CD.
Page 56 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Page 391 - KL: but the cylinder CM is equal to the cylinder EB, and the axis LN to the axis GH; therefore as the cylinder EB to...
Page 110 - If any two points be taken in the circumference of a circle, the straight line which joins them shall fall within the circle.
Page 130 - When you have proved that the three angles of every triangle are equal to two right angles...
Page 183 - FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of...