## The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have Long Ago Vitiated These Books, are Corrected; and Some of Euclid's Demonstrations are Restored. Also the Book of Euclid's Data, in Like Manner Corrected. the first six books, together with the eleventh and twelfth |

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Page 111

PRO B. O inscribe an equilateral and

Let ABCDE be the given circle ; it is required to inscribe an equilateral and

...

PRO B. O inscribe an equilateral and

**equiangular**pentagon in a given circle . CLet ABCDE be the given circle ; it is required to inscribe an equilateral and

**equiangular**pentagon in the circle ABCDE . Describe an isosceles triangle FGH...

Page 112

It is also

circumference DE : If to each be added BCD , the whole ABCD is equal to the

whole EDCB : And the angle AED stands on the circumference ABCD , and the

angle BAE on ...

It is also

**equiangular**; because the cir . cumference AB is equal to thecircumference DE : If to each be added BCD , the whole ABCD is equal to the

whole EDCB : And the angle AED stands on the circumference ABCD , and the

angle BAE on ...

Page 113

... GM , ML are each of them equal to HK or KL : Therefore the pentagon GHKLM

is e . quilateral . It is also

angle FLC , and that the angle HKL is double of the angle FKC , and KLM double

...

... GM , ML are each of them equal to HK or KL : Therefore the pentagon GHKLM

is e . quilateral . It is also

**equiangular**; for , since the angle FKC is equal to theangle FLC , and that the angle HKL is double of the angle FKC , and KLM double

...

Page 114

Let ABCDE be the given equilateral and

inscribe a circle in the pentagon ABCDE . Bifect the angles BCD , CDE by the

straight lines CF , DF , and from the point F in which they meet draw the straight ...

Let ABCDE be the given equilateral and

**equiangular**pentagon ; it is required toinscribe a circle in the pentagon ABCDE . Bifect the angles BCD , CDE by the

straight lines CF , DF , and from the point F in which they meet draw the straight ...

Page 115

10 describe a circle about a given equilateral and eF Let ABCDE be the given

equilateral and

Bisect * the angles BCD , CDE by the straight lines CF , FD , a 9.1 . and from the ...

10 describe a circle about a given equilateral and eF Let ABCDE be the given

equilateral and

**equiangular**pentagon ; it is required to describe a circle about it .Bisect * the angles BCD , CDE by the straight lines CF , FD , a 9.1 . and from the ...

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added alſo altitude angle ABC angle BAC baſe becauſe Book Book XI caſe circle circle ABCD circumference common cone cylinder definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides firſt folid fore four fourth given angle given in poſition given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane produced prop proportionals propoſition pyramid radius rectangle rectangle contained remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC Take taken theſe third triangle ABC wherefore whole

### Popular passages

Page 32 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...

Page 165 - D ; wherefore the remaining angle at C is equal to the remaining angle at F ; Therefore the triangle ABC is equiangular to the triangle DEF.

Page 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Page 10 - When several angles are at one point B, any ' one of them is expressed by three letters, of which ' the letter that is at the vertex of the angle, that is, at ' the point in which the straight lines that contain the ' angle meet one another, is put between the other two ' letters, and one of these two is...

Page 55 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.

Page 32 - ... then shall the other sides be equal, each to each; and also the third angle of the one to the third angle of the other. Let ABC, DEF be two triangles which have the angles ABC, BCA equal to the angles DEF, EFD, viz.

Page 45 - To describe a parallelogram that shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.

Page 211 - AB shall be at right angles to the plane CK. Let any plane DE pass through AB, and let CE be the common section of the planes DE, CK ; take any point F in CE, from which draw FG in the plane DE at right D angles to CE ; and because AB is , perpendicular to the plane CK, therefore it is also perpendicular to every straight line in that plane meeting it (3.

Page 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.

Page 304 - Thus, if B be the extremity of the line AB, or the common extremity of the two lines AB, KB, this extremity is called a point, and has no length : For if it have any, this length must either be part of the length of the line AB, or of the line KB.