 | Charles Hutton - Mathematics - 1812 - 624 pages
...angle APB : it is required to find c, the measure of ACB, supposing there to be known APB = r, BPC =fi, CP = d, BC = L, AC = R. Since the exterior angle of...to the sum of the two interior opposite angles (th. 1 6 Geom.), we have, •with respect to the triangle IAP, AIB = P+IAP; and with regard to the triangle... | |
 | John Gummere - Surveying - 1814 - 398 pages
...took the angle of elevation BAG = 26° 30'. Required the height of the tree. Calculation. 1. Because the exterior angle of a triangle is equal to the sum of the two interior and opposite ones, the angle BDC = DAC + ACD ; therefore ACD - BDC — DAG = 25° : now in the triangle... | |
 | Charles Hutton - Mathematics - 1816 - 618 pages
...required to find c, the measure of AC B, supposing there lobe known APB = p, BPC = /i, CP = d, BC =: i., AC = R. Since the exterior angle of a triangle is...equal to the sum of the two interior opposite angles (tli. 16 Geom.), we have, with respect to the triangle IAP- AIB = P + IAP 5 and with regard to the... | |
 | Olinthus Gregory - Plane trigonometry - 1816 - 276 pages
...staof the centre of 'r the sutnmit of ;Ie APB : it is re* the measure of here to be known p, ce = d,BQ Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we have, with respect to the triangle IAP, AIB = P + IAP; and with regard to the triangle BIC, AIB... | |
 | Charles Hutton - Arithmetic - 1818 - 652 pages
...it is required to find c, the measure of ACB, supposing there to be knOWn AFB = P, BPC = p, CP = (/, BC = L, AC = R. Since the exterior angle of a triangle...the two interior opposite angles (th 16 Geom.), we hare. with respect to the triangle IAP, AIB = p -f- IAP ; and with regard to the triangle BIO, AIB... | |
 | John Farrar - Logarithms - 1822 - 270 pages
...another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, sinre the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have that is 4l° — 23° 45' =17° 15'. Hence in the triangle BAC.... | |
 | Charles Hutton - Geometry - 1826 - 682 pages
...required to find c, ihc measure of ACS, supposing there to be known APB =r P, BPC=/>, cp=d, BC=L, AC=R. Since the exterior angle of a triangle is equal to...Geom.). we have, with respect to the triangle IAP, AIB = p-fiAp ; and with regard to the triangle BIC, AIB=C-}-CBP. Making these two values of AIB equal,... | |
 | Charles Hutton - Mathematics - 1831 - 662 pages
...instrument, or the summit of the observed angle APB : it is required to find c, the measure of ACB, supposing there to be known APB = P, BPC = p, CP =...we have, with respect to the triangle IAP, AIB = P + IAP ; and with regard to the triangle BIC, AIB = c + CBP. Making these two values of AIB equal, and... | |
 | John Farrar - Trigonometry - 1833 - 276 pages
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — ABC = EAC. that is 41° — 23° 45' = 17° 15'. Hence... | |
 | John Farrar - Trigonometry - 1833 - 274 pages
...measure another distance CB = 60 feet in the same direction, and take the angle ABD = 23° 45'. Now, since the exterior angle of a triangle is equal to the sum of the interior opposite angles, we have ACD — A&b = BAC. that is 41° — 23° 45' = 17° 15'. Hence... | |
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Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 
