Bonnycastle's Introduction to Algebra: Containing the Indeterminate and Diophantine Analysis, and the Application of Algebra to Geometry |
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Page 2
... Third edition . 1 vol . 12mo . ENGLISH EXERCISES ; adapted to Murray's English Grammar , consisting of Exercises in Parsing , instances of False Orthography , violations of the Rules of Syntax , Defects in Punctuation ; and violations ...
... Third edition . 1 vol . 12mo . ENGLISH EXERCISES ; adapted to Murray's English Grammar , consisting of Exercises in Parsing , instances of False Orthography , violations of the Rules of Syntax , Defects in Punctuation ; and violations ...
Page 8
... third century after Christ , appears to have been the first , among the ancients , who applied it to the solution of indeterminate or unlimited problems ; but it is to the moderns that we are principally indebted for the most curious re ...
... third century after Christ , appears to have been the first , among the ancients , who applied it to the solution of indeterminate or unlimited problems ; but it is to the moderns that we are principally indebted for the most curious re ...
Page 29
... first term of the divisor ; thus , the first remainder x divided by a , gives C the second a x2 divided by a a term in the quotient ; and the second remainder + x2 gives + a2 the third term , & c . 3 * a સ A 1 a * 8 + 23 03 DIVISION . 29.
... first term of the divisor ; thus , the first remainder x divided by a , gives C the second a x2 divided by a a term in the quotient ; and the second remainder + x2 gives + a2 the third term , & c . 3 * a સ A 1 a * 8 + 23 03 DIVISION . 29.
Page 33
... third ; and so on to the last . * Here , I divide the remainder · 2x2 — 2b2x by — 2xb , ( its greatest simple divisor ) and the quotient is x + b ; and then I divide the last divisor by xb , & c .-- ED . - 3a2 2a 1 ) 4a3 — 2a2 3a + ...
... third ; and so on to the last . * Here , I divide the remainder · 2x2 — 2b2x by — 2xb , ( its greatest simple divisor ) and the quotient is x + b ; and then I divide the last divisor by xb , & c .-- ED . - 3a2 2a 1 ) 4a3 — 2a2 3a + ...
Page 47
... third power , of 2a2 . Ans . 8a , 2. Required the biquadrate , or fourth power , of 2a2x . 2 Ans . 16a3x1 . 3. Required the cube , or third power , of —2y3 . 8 Ans . x®y3 . 27 3a2x 4. Required the biquadrate , or fourth power of 562 ...
... third power , of 2a2 . Ans . 8a , 2. Required the biquadrate , or fourth power , of 2a2x . 2 Ans . 16a3x1 . 3. Required the cube , or third power , of —2y3 . 8 Ans . x®y3 . 27 3a2x 4. Required the biquadrate , or fourth power of 562 ...
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Bonnycastle's Introduction to Algebra: Containing the ..., Pages 1-283 J. Bonnycastle,J. Ryan,J. F. Jenkins No preview available - 2017 |
Common terms and phrases
Algebra answer arise arithmetical arithmetical mean ax² ax³ binomial bx² coefficients consequently cube root cubic equation decimal denominator denoted divisor equal EXAMPLES FOR PRACTICE expression find a number find the square find the sum find the value find two numbers former formula fraction gallons geometrical give given number Given x² greater greatest common measure Hence infinite series last term less logarithms method multiplied negative nth root number of terms perpendicular PROBLEM proportion quadratic equation quadratic surd question quotient rational remain Required the number Required the sum required to divide required to find resolved result rule shillings side square number square root substituted subtracted surd third unknown quantity value of x Whence whole numbers yards
Popular passages
Page 43 - Reduce compound fractions to simple ones, and mixt numbers to improper fractions ; then multiply the numerators together for a new numerator, and the denominators for. a new denominator.
Page 45 - ... required. Or, multiply the quantity into itself as many times, less one, as is denoted by the index of the power, and the last product will be tJie answer.
Page 27 - Divide the first term of the dividend by the first term of the divisor, and write the result as the first term of the quotient. Multiply the whole divisor by the first term of the quotient, and subtract the product from the dividend.
Page 111 - A person has two horses, and a saddle worth £50 ; now, if the saddle be put on the back of the first horse, it will make his value double that of the second ; but if it be put on the back of the second, it will make his value triple that of the first ; what is the value of each horse ? Ans.
Page 29 - In the case here given, the operation of division may be considered as terminated, when the highest power of the letter, in the first, or leading term of the remainder, by which the process is regulated, is less than the...
Page 112 - If A and B together can perform a piece of work in 8 days, A and c together in 9 days, and B and c in 10 days, how many days will it take each person to perform the the same work alone ? Ans.
Page 12 - Q/~\—C = equal to, the sign of equality; signifying that the quantities between which it is placed are equal to each other. Thus...
Page 52 - ... and the quotient will be the next term of the root. Involve the whole of the root, thus found, to its proper power, which subtract from the given quantity, and divide the first term of the remainder by the same divisor as before...
Page 126 - It is required to divide the number 60 into two such parts, that their product shall be to the sum of their squares in the ratio of 2 to 5.
Page 109 - A labourer engaged to serve for 40 days, on condition that for every day he worked he should...