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Ans.
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8 ta

5x +.a 5x2 +- 6ax -+-a
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Ans.
b
x + b

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202 4. It is required to divide by

a +- 203 a ta
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2a + x Ans,

ca + cx +- 2ca

2c4 - 74 co + bc 10. It is required to divide

by
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202 + 62 Ans.

Ans.

359

42

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INVOLUTION.

INVOLUTION is the raising of powers from any proposed root; or the method of finding the square, cube, biquadrate, &c., of any given quantity.

RULE 1.--Multiply the index of the quantity by the index of the power to which it is to be raised, and the result will be the power required.

Or multiply the quantity into itself as many times less one as is denoted by the index of the power, and the last product will be the answer. Note. When the sign of the root is t, all the powers

of it will be t; and when the sign is -, all the even powers will be t, and the odd powers -: as is evident from multiplication.

EXAMPLES. a, the root.

a- the root. a = square.

square.
Q? cube.

ao cube.
a4
4th power.

as 4th power.
as = 5th power. al' = 5th power.
&c.

&c.

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* Any power of the product of two or more quantities is equal to the same power of each of the factors multiplied together. And any power of a fraction is equal to the same power of the numerator divided by the like power of the denominator.

Also, a raised to the nth power is amn; and · am raised to the nth power is £ amn, according as n is an even or an odd number.

EXAMPLES FOR PRACTICE.

1. Required the cube, or third power, of 2a*. Ans. 8a, 2. Required the biquadrate, or fourth power, of 2aRx.

Ans. 16a'4.

3. Required the cube, or third power, of - yo.

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4. Required the biquadrate, or fourth power of

562

81a2c4 Ans.

62568 5. Required the fourth power of a + x;' and the fifth power

Ans. a* + 4x + 6a^x2 + 4ax: +24, and as

5a4y + 10a’ya — 100 ́y3 + 5ayt -- 45. RULE 2.—A binomial or residual quantity may also be readily raised to any power whatever, as follows:

1. Find the terms without the coefficients, by observing that the index of the first, or leading quantity, begins with that of the given power, and decreases continually by 1, in every term to the last; and that in the following quantity, the indices of the terms are 1, 2, 3, 4, &c.

2. To find the coefficients, observe that those of the first and last terms are always l; and that the coefficient of the second term is the index of the power of the first: and for the rest, if the coefficient of any term be multiplied by the index of the leading quantity in it, and the product be divided by the number of terms to that place, it will give the coefficient of the term next following.

Note. The whole number of terms will be one more than the index of the given power; and when both terms of the root are t, all the terms of the power will be t; but if the second term be --, all the odd terms will be t, and the even

; or, which is the same thing, the terms will be + and

alternately.*

terms

172

m

in-1

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* The rule here given, which is the same in the cases of integral powers as in the binomial theorem of Newton, may be expressed in general terms, as follows:

m-1 m-2

–1 – 2 –3 (a+3) =a." +-ma

btm.
2

2 3 &c.

1

-1 M-2 na b+ 2

2 3

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EXAMPLES.

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1. Let a to a be involved, or raised to the fifth power. Here the terms, without the coefficients, are,

a, a-x, a’u, ax, ax4, 25.
And the coefficients, according to the rule, will be

5 X4 10 X3 10 X 25 X 1
1,5,
2
3
4

1 or 1, 5, 10, 10, 5, 1, Whence the entire fifth power of a tæ is

as + 5a4x + 10ax2 + 10u23 + 5axt +- 25. 3. Let a æ be involved, or raised, to the sixth power. Here the terms, without their coefficients, are,

ao, a x, a^x», a 29, a r4, axó, 28. And the coefficients, found as before, are,

6 X 5 15 X 420 X 3'15 X 2 6X1
1, 6,
2
3
4
5

6 or 1, 6, 15, 20, 15, 6, 1. Whence the entire sixth power of a

@@ - 6a x + 15a4x2 20a x + 15aRx4 - 6axó t- 2.6. 3. Required the fourth power of a + x, and the fifth power

Ans. a* t. 4^x +- 60+2x2 + 4ax3 + x4, and as

5a*x + 10aox2 10a-23 + 5ax4 - 25. 5. Required the sixth power of a +b, and the seventh power .

Ans. a 7. 6a b + 15a4b2 + 20a353 + 15a+34 +

6abs +66, and a? Ya®y + 21ay— 35a*y?

+- 350'y* -- 21uRy + 7ay - 77 6. Required the fifth power of 2 + x, and the cube of bac + c.

Ans. 32 + 80x80x2 + 40x3 + 10x4 + 25, and

a + 3a c + 3aca + c3 3a2bx 6acba 30*5x + 3ab x2 + 3cb222 -- 3382

X is

of a

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of a - y.

EVOLUTION.

EVOLUTION, or the extraction of roots, is the reverse of involution, or the raising powers; being the method of finding the square root, cube root, &c., of any given quantity.

CASE I. To find any root of a simple quantity. RULE.-Extract the root of the coefficient for the numeral

&c. which formulæ will also equally hold when m is a fraction, as will be more fully explained hereafter. It may

also be farther observed, that the sum of the coefficients in every power, is equal to the number 2 raised to that power. Thus 1+1 = 2, for the first power; 1+2+1=4= 22, for the square; 1+3+3+1 8=23, for the cube, or third power; and so on.

part, and the root of the quantity subjoined to it for the literal part; then these joined together, will be the root required.

And if the quantity proposed be a fraction, its root will be found by taking the root both of its numerator and denominator.

Note. The square root, the fourth root, or any other even root, of an affirmative quantity, may be either + or Thus va? = ta or d, and 484 + b or – b, &c. But the cube root, or any other odd root, of a quantity, will have the same sign as the quantity itself. Thus,

=d; y 003 a; and v-as It may here, also, be farther remarked, that any even root of of a negative quantity is unassignable.

Thus, v-am cannot be determined, as there is no quan. tity, either positive or negative, (+ or -), that, when multiplied by itself, will produce - a?.

3

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EXAMPLES.

aic

and v

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1. Find the square root of 9x2, and the cube root of 8x3.

Here ✓ 9x2 ✓9 x V x2 = 3 X X = 3x. Ans.
And X 823 V 8 X 83 2 X X = 2x. Ans.

a2x2 2. It is required to find the square root of and the

4c2
Bars
cube root of

2703•
a x2
va xa

Baa 2ax
Here
4c2
2c

2763

3c * 3. It is required to find the square root of 4u2x6.

Ans. 2ax. 4. It is required to find the cube root of 1250x.

Ans. 5axl. 5. It is required to find the 4th root of 2560*28.

Ans. 4ax

404 6. It is required to find the square root of

9x®y?

202 Ans.

3xy 8a3

2a 7. It is required to find the cube root of

Ans. 125x6.

5.22 * The reason why ta and --- Q are each the square root of 62 is obvious, since, by the rule of multiplication, (ta) X(ta) and (ma) X (a) are both equal to a2.

And for the cube root, fifth root, &c., of a negative quantity, it is plain, from the same rule, that (max(-a)X(-a)=-23; and (-a) x(+22) = And consequently 3 a, and v-as

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