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INVOLUTION is the raising of powers from any proposed root; or the method of finding the square, cube, biquadrate, &c., of any given quantity.

RULE 1-Multiply the index of the quantity by the index of the power to which it is to be raised, and the result will be the power required.

Or multiply the quantity into itself as many times less one as is denoted by the index of the power, and the last product will be the answer.

Note. When the sign of the root is +, all the powers of it will be ; and when the sign is all the even powers

2

will be +, and the odd powers as is evident from mul

tiplication.*

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203

a the root.

a

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ax + a2

2ax + a2 square.

α

2ax2 + a2x
ax2+2a2x — a3

x + a the root.
x + a

x2 + ax

+ax +a2

x2+2ax + a2 square.

x + a

x2 + 3ax2 + a2

+ax2+2a2x + a3

3ax2+3a2x-a3 cube.x3 + 3ax2 + 3a2x + a3 cube.

* Any power of the product of two or more quantities is equal to the same power of each of the factors multiplied together. And any power of a fraction is equal to the same power of the numerator divided by the like power of the denominator.

Also, am raised to the nth power is amn; and am raised to the nth power is amn, according as n is an even or an odd number.

EXAMPLES FOR PRACTICE.

1. Required the cube, or third power, of 2a2.

Ans. 8a,

2. Required the biquadrate, or fourth power, of 2a2x.

2

Ans. 16a3x1.

3. Required the cube, or third power, of —2y3.

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4

5. Required the fourth power of a + x; and the fifth power of a-y. 3 Ans. a1 + 4a3x + 6a2x2 + 4ɑx3 +x1, and as 5a3y + 10a3y2 — 10a2y3 + 5ay1 — y3. RULE 2.—A binomial or residual quantity may also be readily raised to any power whatever, as follows:

1. Find the terms without the coefficients, by observing that the index of the first, or leading quantity, begins with that of the given power, and decreases continually by 1, in every term to the last; and that in the following quantity, the indices of the terms are 1, 2, 3, 4, &c.

2. To find the coefficients, observe that those of the first and last terms are always 1; and that the coefficient of the second term is the index of the power of the first and for the rest, if the coefficient of any term be multiplied by the index of the leading quantity in it, and the product be divided by the number of terms to that place, it will give the coefficient of the term next following.

Note. The whole number of terms will be one more than the index of the given power; and when both terms of the root are +, all the terms of the power will be ; but if the second term be -, all the odd terms will be +, and the even terms ; or, which is the same thing, the terms will be + and alternately.*

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* The rule here given, which is the same in the cases of integral powers as in the binomial theorem of Newton, may be expressed in general terms, as follows:

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m 1

1 Ն

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m.

2

a

1 m a

2

- m

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2

-1 m2 m-3. Im

-a

b3,

3

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EXAMPLES.

1. Let a +x be involved, or raised to the fifth power. Here the terms, without the coefficients, are,

5

a3, aax, a3x2, a2x23, αx1, x5.

And the coefficients, according to the rule, will be 5 X 4 10 X 3 10 X 2 5 X 1

1, 5,

2

or 1, 5, 10,

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Whence the entire fifth power of a +x is

2

3

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a5 + 5a*x + 10a3x2 + 10a2x3 + 5ax2 + x3.

3. Let a x be involved, or raised, to the sixth power. Here the terms, without their coefficients, are,

a®, a2x, a2x2, a3x3, a2x2, ax3, x6.

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And the coefficients, found as before, are,

6X5 15 X 4 20 X 3 15 X 2 6 × 1

1, 6,

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or 1, 6, 15, 20, 15,

Whence the entire sixth power of a

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ασ 6a5x+15a2x2 20a3x3 +15a2xa

3. Required the fourth power of a + x, and the fifth power ac. Ans. a1+4a3x + 6a2x2 + 4ax3 + x1, and a3

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5. Required the sixth power of a + b, and the seventh power Ans. a6ab + 15a2b2 + 20a3b3 + 15a2ba + 6ab5b, and a7-7aoy +21a3y2-35a1y3 + 35a3y* — 21a2y3 + 7ay® — y1.

α

6. Required the fifth power of 2+x, and the cube of a- bx + c. Ans. 32 +80x + 80x2 + 40x3 + 10x2 + x3, and a3 +3a2c + 3ac2 + c3 3a2bx 6acbx

3c2 bx +3ab2x2 + 3cb2x2 - b3x3.

EVOLUTION.

EVOLUTION, or the extraction of roots, is the reverse of involution, or the raising powers; being the method of finding the square root, cube root, &c., of any given quantity.

CASE I.

To find any root of a simple quantity.

RULE.-Extract the root of the coefficient for the numeral

&c. which formulæ will also equally hold when m is a fraction, as will be more fully explained hereafter.

It may also be farther observed, that the sum of the coefficients in every power, is equal to the number 2 raised to that power. Thus 1+I =2, for the first power; 1+2+1=4= 22, for the square; 1+3+3+1 =8=23, for the cube, or third power; and so on.

part, and the root of the quantity subjoined to it for the literal part; then these joined together, will be the root required.

And if the quantity proposed be a fraction, its root will be found by taking the root both of its numerator and denominator. Note. The square root, the fourth root, or any other even root, of an affirmative quantity, may be either + or Thus

√ a2

+ a or

a, and 4/b4 +bor - b, &c. But the cube root, or any other odd root, of a quantity, will have the same sign as the quantity itself. Thus, 3/ a3 = a a; 3/ a3 -a; and 5/ a, &c.* It may here, also, be farther remarked, that any even root of of a negative quantity is unassignable.

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a5

Thus, a cannot be determined, as there is no quantity, either positive or negative, (+ or -), that, when multiplied by itself, will produce

a3.

α.

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a2x2

2. It is required to find the square root of

and the

4c2

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3. It is required to find the square root of 4a2x®.

4. It is required to find the cube root of

5. It is required to find the 4th root of 256a1x3.

Ans. 2ax3. 125a3x6.

Ans. 5ax2.

Ans. 4ax.

4a4

6. It is required to find the square root of

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* The reason why +a and -a are each the square root of a2 is obvious, since, by the rule of multiplication, (-+a) ×(+a) and (~a) X (-a) are both equal to a2.

And for the cube root, fifth root, &c., of a negative quantity, it is plain, from the same rule, that (-a)X(-a) × (—a) = And consequently 3/

аз

a3; and (a3) × (+α2)=

a, and 5-a5

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