Intermediate Geometry: Being Sections V and VI of "geometry, Theoretical and Practical".W.B. Clive, University Tutorial Press Ld., 1908 - Geometry |
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Page 404
... A B C D ' Thus A = λB , C = λD . A λB B - - λD D ( iv ) If the quantities A , B , C , D , E , F ... are all of the same kind , and if A : B = h : k , C : D h : k , E : F = h : k .. then ( A + C + E + . . . ) : ( B + D + F + . . . ) = hk ...
... A B C D ' Thus A = λB , C = λD . A λB B - - λD D ( iv ) If the quantities A , B , C , D , E , F ... are all of the same kind , and if A : B = h : k , C : D h : k , E : F = h : k .. then ( A + C + E + . . . ) : ( B + D + F + . . . ) = hk ...
Page 414
... ABCD is a quadrilateral and P is any point . Prove that the centroids of the triangles PAB , PBC , PCD , PDA form a parallelogram . 5. OA , OB are any two straight lines intersecting in O , and R and S are any two points on OB , OA ...
... ABCD is a quadrilateral and P is any point . Prove that the centroids of the triangles PAB , PBC , PCD , PDA form a parallelogram . 5. OA , OB are any two straight lines intersecting in O , and R and S are any two points on OB , OA ...
Page 422
... ABCD is inscribed in a circle , and the two sides BA and CD are produced to meet in O ; prove that the triangles OAD and OBC are similar . 7. If two straight lines AOD , BOC cut one another internally or externally in 0 , so that OA ...
... ABCD is inscribed in a circle , and the two sides BA and CD are produced to meet in O ; prove that the triangles OAD and OBC are similar . 7. If two straight lines AOD , BOC cut one another internally or externally in 0 , so that OA ...
Page 423
... ABCD is a parallelogram , L , M and P are points in AD , CD , BD respectively , LP and MP meet BC , BA respectively in No and 0. Prove that LM is parallel to ON . 27. ABCD is a quadrilateral . On the side of AB remote from C , LBAE is ...
... ABCD is a parallelogram , L , M and P are points in AD , CD , BD respectively , LP and MP meet BC , BA respectively in No and 0. Prove that LM is parallel to ON . 27. ABCD is a quadrilateral . On the side of AB remote from C , LBAE is ...
Page 433
... ABCD and EFGH are two equiangular quadrilaterals , and AB : EF = CD : GH . Prove that the quadrilaterals are similar . Is there any exception to this ? = = 30. ABCD is a quadrilateral , and P , Q , R , S are points on AB , BC , CD , DA ...
... ABCD and EFGH are two equiangular quadrilaterals , and AB : EF = CD : GH . Prove that the quadrilaterals are similar . Is there any exception to this ? = = 30. ABCD is a quadrilateral , and P , Q , R , S are points on AB , BC , CD , DA ...
Other editions - View all
Intermediate Geometry: Being Sections V and VI of Geometry, Theoretical and ... Walter Percy Workman No preview available - 2023 |
Intermediate Geometry: Being Sections V and VI of Geometry, Theoretical and ... Walter Percy Workman No preview available - 2023 |
Intermediate Geometry: Being Sections V and VI of Geometry, Theoretical and ... Walter Percy Workman No preview available - 2019 |
Common terms and phrases
ABCD B.Sc base bisects centre of similitude Ceva's Theorem CHAPTER chord circles touch circumcircle collinear concurrent concyclic points Cons Cons.-Draw cyclic quadrilateral diagonals diameter dihedral angle divided equiangular EXERCISES externally figure Find the locus Geometry given circles given line given point given ratio given straight line harmonic range Hence hypotenuse intersecting planes irrational numbers LAOB LDPE lies in plane line drawn line joining line perpendicular mean proportional meet nine-point circle opposite edges orthocentre pair parallel planes parallelogram parallelopiped perpendicular Picture Plane plane X plane XX polygon Proof quadrilateral radical axis radii radius rational numbers rectangle contained remaining Theorems Required to prove respectively right angles segments similar triangles Similarly solid angle square tangents tetrahedron THEOREM.-If three lines triangle ABC Tutorial vertex vertical angle
Popular passages
Page 570 - If, at a point in a straight line, two other straight lines, upon the opposite sides of it, make the adjacent angles together equal to two right angles, these two straight lines shall be in one and the same straight line.
Page 584 - If from the vertical angle of a triangle a straight line be drawn perpendicular to the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the perpendicular and the diameter of the circle described about the triangle.
Page 575 - The square described on the hypothenuse of a rightangled triangle is equal to the sum of the squares described on the other two sides.
Page 424 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.
Page 10 - The historical part is concise and clear, but the criticism is even more valuable, and a number of illustrative extracts contribute a most useful feature to the volume.
Page 571 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Page 16 - The object of the UNIVERSITY TUTORIAL SERIES is to provide candidates for examinations and learners generally with text-books which shall convey in the simplest form sound instruction in accordance with the latest results of scholarship and scientific research. Important points are fully and clearly treated, and care has been taken not to introduce details which are likely to perplex the beginner. The Publisher will be happy to entertain applications from Schoolmasters for specimen copies of any...
Page 583 - If four straight lines be proportionals, the rectangle contained by the extremes is equal to the rectangle contained by the means...
Page 574 - If a parallelogram and a triangle be on the same base and between the same parallels, the parallelogram shall be double of the triangle.
Page 574 - Equal triangles, on equal bases, in the same straight line, and on the same side of it, are between the same parallels. Let...