Mathematical Modeling: A Chemical Engineer's PerspectiveMathematical modeling is the art and craft of building a system of equations that is both sufficiently complex to do justice to physical reality and sufficiently simple to give real insight into the situation. Mathematical Modeling: A Chemical Engineer's Perspective provides an elementary introduction to the craft by one of the century's most distinguished practitioners. Though the book is written from a chemical engineering viewpoint, the principles and pitfalls are common to all mathematical modeling of physical systems. Seventeen of the author's frequently cited papers are reprinted to illustrate applications to convective diffusion, formal chemical kinetics, heat and mass transfer, and the philosophy of modeling. An essay of acknowledgments, asides, and footnotes captures personal reflections on academic life and personalities.
|
From inside the book
Results 1-5 of 81
... Surface-Reaction Model 282 M. A. McKARNIN, R. ARIS, AND L. D. SCHNMIDT Introduction 282 Surface Reaction Model 283 Bifurcation Analysis 286 (a) Model Symmetry 286 (b) Steady-State Bifurcations 287 . The Stability of the Steady States ...
... Surface Reaction Model 307 M. A. McKARNIN, L. D. SCHNAIDT, AND R ARIS Introduction 307 Surface Reaction Model 309 Mathematical and Numerical Framework 311 Excitation Diagram 314 (a) Small and Large Forcing Amplitudes 316 (b) Local ...
... surface of o, of which dS is the surface element. This surface integral can be written as a volume integral by the application of Green's theorem JJJ f-n dS = JJJ A. f dV, where Af = (of 10x + f/dy +f/0z). Then, bringing all terms to ...
... surface must be continuous, for the surface has no capacity to hold anything or volume to generate anything. Because there can be no accumulation in the surface, the flux up to it from one side must equal the flux away from it on the ...
... surface of the sphere the concentration of the solute is S, the saturation solubility, and far from the sphere it is zero. Thus, dN/dt = (4tr°p,/m)(dr/dt) = -k,4tr?(S - 0). (81) Let X = Sm/p, so that dr/dt = ->k. (82) We will use the ...
Contents
MATTER | 105 |
MISCELLANEA | 417 |
BIBLIOGRAPHY | 455 |
INDEX OF GRADUATE STUDENTS AND COAUTHORS | 467 |
SUBJECT INDEX TO THE PAPERS IN THE BIBLIOGRAPHY | 469 |
INDEX | 473 |