| Robert Simson - Trigonometry - 1762 - 466 pages
...ftraight line AC making any angle with AB ; and in AC take any point D, and take AC which is the fam« **multiple of AD that AB is of the part which is to...join BC, and draw DE parallel to it. then AE is the** fame part of AB that AD is of AC ; that is, AE is the part required to be cut off. Becaufe ED is parallel... | |
| Robert Simson - Trigonometry - 1775 - 520 pages
...requi- gee N. fed. Let AB be the given ftraight line ; it is required to cut off any part from it. Fiom **the point A draw a ftraight line AC making any angle...parallel to one of the fides of the triangle ABC,** viz.toBC,asCD is to DA, fois'BE to EA ; and, by compofition b, CA is to AD, as BA to AE : But CA is... | |
| John Playfair - Trigonometry - 1795 - 400 pages
...and in AC take any point D, and take AC M 4 the Book VI. the fame multiple of AD, that AB i? - f - **of the part which is to be cut off from it ; join...one of the fides of the triangle ABC, viz. to BC,** a i. 6. as CD is to DA, fo is» BE to EA; and, 6.18. 5. by compofition b, CA is to AD, as BA to, AE... | |
| Euclid, John Playfair - Circle-squaring - 1804 - 440 pages
...take AC M 4 fnch Book VI «t. '. b i«. 5. fuch that it fhall contain AD, as oft as AB js to contain **the part, which is to be cut off from it ; join BC,...one of the fides of the triangle ABC, viz. to BC,** CD : DA : : BE : EA » ; and by compofition b, CA : AD : : BA : AE : But CA is a multiple of AD ; therefore... | |
| Robert Simson - Trigonometry - 1804
...ftraight line AC making any angle with AB; and in AC take any point D, and take AC which is the ftme **multiple of AD that AB is of the part which is to...join BC, and draw DE parallel to it. then AE is the** fame part of AB that AD is of AC ; that is, AE is the part required to be cut off. Becaufe ED is parallel... | |
| John Playfair - Euclid's Elements - 1806 - 311 pages
...; in AC take any point D, and take AC sucli that it shall contain AD as" often as AB is to contain **the part which is to be cut off from it ; join BC,...to it ; then AE is the part required to be cut off.** Because ED is parallel to BC, one of the sides of the triangle ABC, CD : DA : : BE : EAa ; therefore,... | |
| Robert Simson - Trigonometry - 1806 - 518 pages
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to be cut off from it ; join** DC, and draw DE parallel to it : then AE is the part required to be cut off. Because ED is parallel... | |
| Euclid - Geometry - 1810 - 518 pages
...draw a straight line AC making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...to it : then AE is the part required to be cut off.** Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as CD is to / \ DA, so... | |
| Euclides - 1816 - 528 pages
...draw a straight line AC, making any angle with AB ; and in AC take any point D, and take AC the same **multiple of AD, that AB is of the part which is to...to it: Then AE is the part required to be cut off.** . Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, as CD is to DA, so isa... | |
| John Playfair - Circle-squaring - 1819 - 333 pages
...; and in AC take any point D, and take AC such that it shall contain AD, as oft as AB is to contain **the part, which is to be cut off from it ; join BC,...to it : then AE is the part required to be cut off.** Because ED is parallel to one of the sides of the triangle ABC, viz. to BC, CD : DA : : DK : 1^(2^6.)... | |
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