## The First Six Books: Together with the Eleventh and Twelfth |

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Page 51

PRO P. I , THE O R. F into any number of parts ; the

PRO P. I , THE O R. F into any number of parts ; the

**rectangle**contained by the two straight lines , is equal to the**rectangles**contained by the undivided line , and the several parts of the divided line . Let D 2 Book II . a II . Page 52

І. Let A and BC be two straight lines ; and let BC be divided into any parts in the points D , E ; the

І. Let A and BC be two straight lines ; and let BC be divided into any parts in the points D , E ; the

**rectangle**contained by the straight lines A , BC is equal to the**rectangle**contained by A , B D E C BD , together with that contain ... Page 53

and AF is the

and AF is the

**rectangle**contained by BA , AC ; for it is con- Book II . tained by DA , AC , of which AD is equal to AB ; and CE is contained by AB , BC , for BE is equal to AB ; therefore the**rectangle**contained by AB , AC , together ... Page 54

... and that AG is the

... and that AG is the

**rectangle**contain : ed by AC , CB , for GC is equal to CB ; therefore GE is also equal to the**rectangle**AC , CB ; wherefore AG , GE are equal to twice the**rectangle**AC , CB : And HF , CK are the squares of AC ... Page 55

PRO P. V. THEOR . ti a straight line be divided into two equal parts , and also into two unequal parts ; the

PRO P. V. THEOR . ti a straight line be divided into two equal parts , and also into two unequal parts ; the

**rectangle**contained by the unequal parts , together with the square of the line between the points of fe & tion , is equal to ...### What people are saying - Write a review

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### Common terms and phrases

added alſo altitude angle ABC angle BAC baſe becauſe Book caſe centre circle circle ABCD circumference common cone cylinder definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides figure firſt folid fore four fourth given angle given in poſition given in ſpecies given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane priſm produced prop proportionals propoſition pyramid reaſon rectangle rectangle contained rectilineal remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC Take taken theſe third triangle ABC wherefore whole

### Popular passages

Page 483 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.

Page 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Page 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...

Page 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.

Page 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.

Page 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.

Page 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.

Page 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...

Page 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...

Page 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.