## The First Six Books: Together with the Eleventh and TwelfthJ. Balfour, 1781 - 520 pages |

### From inside the book

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**fame**Number and Mag- nitude , and yet be unequal to one another ; as shall be made evident in the Notes fubjoined to thefe Elements . In like**manner**, in the Demonftration of the 26th Prop . of the 11th Book , it is taken for granted ... Page 23

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**fame manner**, because ABD is a ftraight line , the angle DBE is equal to the angle EBA ; where- fore the angle DBE is equal to the angle CBE , the lefs to the greater ; which is impoffible ; therefore two ftraight lines can- A not have ... Page 25

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**fame**ftraight line with BC . And , in like**manner**, it may be demonftrated , that no other can be in the**fame**ftraight line with it but BD , which therefore is in the**fame**ftraight line with CB . Wherefore , if at a point , & c ... Page 26

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**fame manner**, if the fide BC be bifected , it may be demonstrated that the angle BCG , that is d , the angle ACD , is greater than the angle ABC . Therefore , if one fide , & c . Q. E. D. A PROP . XVII . THEOR . NY two angles of a ... Page 28

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**fame manner**it may be demonstrated , that the fides AB , BC are greater than CA , and BC , CA greater than AB . Therefore any two fides , & c . Q. E. D. PRO P. XXI . THEOR . IF , from the ends of the fide of a triangle , there be drawn ...### Other editions - View all

### Common terms and phrases

alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio bifected Book XI cafe centre circle ABCD circumference cone confequently cylinder defcribed demonftrated drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fide BC fides fimilar firft firſt folid angle fome fore fphere fquare of AC ftraight line AB ftraight line BC given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs likewife oppofite parallel parallelepipeds parallelogram perpendicular plane angles prifms PROP propofition pyramid ratio of BC rectangle contained rectilineal figure right angles ſquare thefe THEOR theſe triangle ABC wherefore

### Popular passages

Page 472 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.

Page 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Page 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...

Page 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.

Page 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.

Page 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.

Page 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.

Page 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...

Page 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...

Page 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.