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ABCD acute adjacent altitude Appl approaches base bisector bisects called centre chord circle circumference circumscribed coincidence common Cons construct diagonals diameter difference distance divided Draw drawn equal equilateral triangle equivalent EXERCISES extremities feet figure Find Find the area formed four geometric given given circle given point greater hexagon homologous hypotenuse included inscribed intersecting isosceles triangle joining length limit locus logarithm mantissa mean measure median meet middle point OO OO OO parallel parallelogram passes perimeter perpendicular polygon Problem produced proof proportional PROPOSITION Prove quadrilateral radii radius ratio rectangle respectively right angle right triangle secant segments sides similar square straight line tangent Theorem touch trapezoid triangle ABC variable vertex
Page 60 - A circle is a plane figure bounded by a curved line, called the circumference, every point of which is equally distant from a point within called the center.
Page 139 - In any obtuse triangle, the square of the side opposite the obtuse angle is equal to the sum of the squares of the other two sides, increased by twice the product of one of these sides and the projection of the other side upon it.
Page 44 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Page 43 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Page 217 - Show that the areas of similar triangles are to each other as the squares of the homologous sides.
Page 89 - Four quantities are in proportion when the ratio of the first to the second is equal to the ratio of the third to the fourth.
Page 107 - If in a right triangle a perpendicular is drawn from the vertex of the right angle to the hypotenuse : I.
Page 218 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. B' ADC A' D' C' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove = — • A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.