A Treatise on Refrigerating and Ice-making Machinery ...Colliery Engineer Company, 1899 |
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Page 59
... ton . Ice - melting capacity , tons per twenty - four hours . * 39 . Refrigerating effect , pounds of ice per pound of coal . 40 . ' HEAT BALANCE . Heat given to ammonia by brine per minute , B. T. U. Heat given to ammonia by compressor ...
... ton . Ice - melting capacity , tons per twenty - four hours . * 39 . Refrigerating effect , pounds of ice per pound of coal . 40 . ' HEAT BALANCE . Heat given to ammonia by brine per minute , B. T. U. Heat given to ammonia by compressor ...
Page 82
... tons . = - Then , F = H 285,300 ' ( 109. ) Art . 1338 . F = h 11,887.5 ' ( 110. ) Art . 1338 . THEORETICAL MAXIMUM EFFICIENCY OF A HEAT ENGINE . Let E theoretical maximum efficiency ; Q1 = heat given up by the hot body in B. T. U .; Q1 ...
... tons . = - Then , F = H 285,300 ' ( 109. ) Art . 1338 . F = h 11,887.5 ' ( 110. ) Art . 1338 . THEORETICAL MAXIMUM EFFICIENCY OF A HEAT ENGINE . Let E theoretical maximum efficiency ; Q1 = heat given up by the hot body in B. T. U .; Q1 ...
Page 92
... tons per 24 hours is F = 24 × 60 × n M [ r , — ( te — ta ) ] 285,300 .00505 [ r , — ( t 。— ta ) ] · ― - = ( 123. ) Art . 1373 . QUANTITY OF BRINE REQUIRED to REFRIGERATE A GIVEN SECTION . 25 T G = t2 — t 、 in which G = ( 124. ) Art ...
... tons per 24 hours is F = 24 × 60 × n M [ r , — ( te — ta ) ] 285,300 .00505 [ r , — ( t 。— ta ) ] · ― - = ( 123. ) Art . 1373 . QUANTITY OF BRINE REQUIRED to REFRIGERATE A GIVEN SECTION . 25 T G = t2 — t 、 in which G = ( 124. ) Art ...
Page 93
... tons of ice , is F = .00505 n M [ r , — ( t . - ta ) ] , and the weight M of ― ammonia circulated per stroke is M = C ข = Cw , where C denotes the volume of the compressor cylinder in cubic feet , the volume of a pound of ammonia vapor ...
... tons of ice , is F = .00505 n M [ r , — ( t . - ta ) ] , and the weight M of ― ammonia circulated per stroke is M = C ข = Cw , where C denotes the volume of the compressor cylinder in cubic feet , the volume of a pound of ammonia vapor ...
Page 94
... ton for 4 cubic feet of piston displacement per minute . With double - acting compressors , allow 5 to 6 cubic feet per minute for each ton . DIRECT MEASUREMENT OF AMMONIA . The formula for capacity applies to compressors working under ...
... ton for 4 cubic feet of piston displacement per minute . With double - acting compressors , allow 5 to 6 cubic feet per minute for each ton . DIRECT MEASUREMENT OF AMMONIA . The formula for capacity applies to compressors working under ...
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Common terms and phrases
1-inch pipe 24 hours A₁ absolute temperature abstracted from cold ADIABATIC EXPANSION clearance coil cold body compression compressor condensing water corresponding Cosine Sine Cosine Cotang Tang Cotang crank-pin in ft cubic feet cubic foot cut-off denote the weight direct-expansion system expansion cylinder following formula foot-pounds heat absorbed heat abstracted heat delivered heat given heat of vaporization horsepower ice-melting capacity latent heat leaves the condenser logarithm machine mantissa number of revolutions p₁ V₁ P₂ piston pound of steam pounds per square pressure in pounds PV log Q₁ Q₂ quantity of brine ratio of expansion refrigerating capacity refrigeration required revolutions per minute s₂ Sine Cosine Sine Specific Gravity specific heat square inch strokes per minute superheated t₁ t₂ Tang Cotang Tang tons of refrigeration total heat V₂ velocity volume and pressure volume in cubic w₁ W₂ weight in pounds ΙΟ
Popular passages
Page 63 - W= weight of body at the surface; w = weight of a body at a given distance above or below the surface ; d= distance between the center of the earth and the center of the body ; R = radius of the earth = 4,000 miles.
Page 61 - To Divide One Number by Another, Subtract the logarithm of the divisor from the logarithm of the dividend, and obtain the antilogarithm of the difference.
Page 59 - X 10") - 3.8156. If the number is less than 1, the characteristic is negative and is numerically one greater than the number of zeros immediately following the decimal point. To avoid having a negative integral part and a positive decimal part, the characteristic is written as a difference.
Page 59 - For a number wholly decimal, the characteristic is negative, and is numerically one greater than the number of ciphers between the decimal point and the first digit of the decimal.
Page 66 - Law. — The temperature remaining the same, the volume of a given quantity of gas varies inversely as the pressure.
Page 59 - Law of Sines — In any triangle, the sides are proportional to the sines of the opposite angles. That is, sin A = sin B...
Page 61 - Multiply the logarithm of the number by the exponent which denotes the power to which the number is to be raised, and the result will be the logarithm of the required power. EXAMPLE. — What is the square of (a) 7.92 ? (6) the cube of 94.7? (<-) the 1.6 power of 512. that is, 5121-* ? SOLUTION.— (a) Log 7.92 = .89873; the exponent of the power is 2.
Page 24 - I .57381 .81899 .58802 .80885 .60205 .79846 .6.589 .78783 .62955 .77696 59 2 .57405 .81882 .58826 .80867 .60228 .79829 .61612 •78765 .62977 .77678 58 3 .57429 .81865 .58849 .80850 .60251 .79811 .61635 •78747 .63000 .77660 57...
Page 20 - ... •93979 I 60 .27564 .96126 •29237 •95630 .30902 .95106 .32557 .94552 .34202 •93969 0 / Cosine Sine Cosine Sine Cosine Sine Cosine Sine Cosine Sine...
Page 77 - ... however, it is more convenient to reject the air into the cooler D and draw the fresh supply from the atmosphere, which has a much higher temperature. In this case, it is evident that the air does not return to its original state in the cooler, and the cycle is not closed. 1345. General Theory. — In the following discussion, it will be assumed, for the sake of simplicity, that compression and expansion are adiabatic and that the air is drawn into the compressor from the cooling chamber, so...