A Treatise on Refrigerating and Ice-making Machinery ...Colliery Engineer Company, 1899 |
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Page 60
... length of the other parallel side ; area of trapezoid . A = h 1⁄2 ( 1 + 4 ) . ( 45. ) Art . 376 . THE TRIANGLE . A ... lengths , respectively , of 60 TABLES AND FORMULAS .
... length of the other parallel side ; area of trapezoid . A = h 1⁄2 ( 1 + 4 ) . ( 45. ) Art . 376 . THE TRIANGLE . A ... lengths , respectively , of 60 TABLES AND FORMULAS .
Page 61
a and b = the lengths , respectively , of the two short sides of a right - angled triangle ; c = length of third side , or hypotenuse . c = √ a2 + b2 . ( 49. ) Art . 385 . a = √c2 = b2 . - b = √ c2 — a2 . ( 50. ) Art . 385 . - h ...
a and b = the lengths , respectively , of the two short sides of a right - angled triangle ; c = length of third side , or hypotenuse . c = √ a2 + b2 . ( 49. ) Art . 385 . a = √c2 = b2 . - b = √ c2 — a2 . ( 50. ) Art . 385 . - h ...
Page 68
... length of space passed over uniformly ; the time occupied in passing over the space S ; V the velocity . t = V : v = $ S ( 7. ) Art . 859 . ( 8. ) Art . 859 . S = Vt . t = S Ꮴ ( 9. ) Art . 859 . MASS , WEight , and GRAVITY . If the ...
... length of space passed over uniformly ; the time occupied in passing over the space S ; V the velocity . t = V : v = $ S ( 7. ) Art . 859 . ( 8. ) Art . 859 . S = Vt . t = S Ꮴ ( 9. ) Art . 859 . MASS , WEight , and GRAVITY . If the ...
Page 74
... length of any body ; / = amount of expansion or contraction due to heat- ing or cooling the body ; A = area of any section of the body ; a = increase or decrease of area of the same 74 TABLES AND FORMULAS . Unequal Volumes and Pressures.
... length of any body ; / = amount of expansion or contraction due to heat- ing or cooling the body ; A = area of any section of the body ; a = increase or decrease of area of the same 74 TABLES AND FORMULAS . Unequal Volumes and Pressures.
Page 79
... length of stroke in ft .; N the No. of strokes per min . = Then , the work done per minute is PL A N foot - pounds . One horsepower 33,000 foot - pounds per min . = Therefore , the indicated horsepower of the engine is found from the ...
... length of stroke in ft .; N the No. of strokes per min . = Then , the work done per minute is PL A N foot - pounds . One horsepower 33,000 foot - pounds per min . = Therefore , the indicated horsepower of the engine is found from the ...
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Common terms and phrases
1-inch pipe 24 hours A₁ absolute temperature abstracted from cold ADIABATIC EXPANSION clearance coil cold body compression compressor condensing water corresponding Cosine Sine Cosine Cotang Tang Cotang crank-pin in ft cubic feet cubic foot cut-off denote the weight direct-expansion system expansion cylinder following formula foot-pounds heat absorbed heat abstracted heat delivered heat given heat of vaporization horsepower ice-melting capacity latent heat leaves the condenser logarithm machine mantissa number of revolutions p₁ V₁ P₂ piston pound of steam pounds per square pressure in pounds PV log Q₁ Q₂ quantity of brine ratio of expansion refrigerating capacity refrigeration required revolutions per minute s₂ Sine Cosine Sine Specific Gravity specific heat square inch strokes per minute superheated t₁ t₂ Tang Cotang Tang tons of refrigeration total heat V₂ velocity volume and pressure volume in cubic w₁ W₂ weight in pounds ΙΟ
Popular passages
Page 63 - W= weight of body at the surface; w = weight of a body at a given distance above or below the surface ; d= distance between the center of the earth and the center of the body ; R = radius of the earth = 4,000 miles.
Page 61 - To Divide One Number by Another, Subtract the logarithm of the divisor from the logarithm of the dividend, and obtain the antilogarithm of the difference.
Page 59 - X 10") - 3.8156. If the number is less than 1, the characteristic is negative and is numerically one greater than the number of zeros immediately following the decimal point. To avoid having a negative integral part and a positive decimal part, the characteristic is written as a difference.
Page 59 - For a number wholly decimal, the characteristic is negative, and is numerically one greater than the number of ciphers between the decimal point and the first digit of the decimal.
Page 66 - Law. — The temperature remaining the same, the volume of a given quantity of gas varies inversely as the pressure.
Page 59 - Law of Sines — In any triangle, the sides are proportional to the sines of the opposite angles. That is, sin A = sin B...
Page 61 - Multiply the logarithm of the number by the exponent which denotes the power to which the number is to be raised, and the result will be the logarithm of the required power. EXAMPLE. — What is the square of (a) 7.92 ? (6) the cube of 94.7? (<-) the 1.6 power of 512. that is, 5121-* ? SOLUTION.— (a) Log 7.92 = .89873; the exponent of the power is 2.
Page 24 - I .57381 .81899 .58802 .80885 .60205 .79846 .6.589 .78783 .62955 .77696 59 2 .57405 .81882 .58826 .80867 .60228 .79829 .61612 •78765 .62977 .77678 58 3 .57429 .81865 .58849 .80850 .60251 .79811 .61635 •78747 .63000 .77660 57...
Page 20 - ... •93979 I 60 .27564 .96126 •29237 •95630 .30902 .95106 .32557 .94552 .34202 •93969 0 / Cosine Sine Cosine Sine Cosine Sine Cosine Sine Cosine Sine...
Page 77 - ... however, it is more convenient to reject the air into the cooler D and draw the fresh supply from the atmosphere, which has a much higher temperature. In this case, it is evident that the air does not return to its original state in the cooler, and the cycle is not closed. 1345. General Theory. — In the following discussion, it will be assumed, for the sake of simplicity, that compression and expansion are adiabatic and that the air is drawn into the compressor from the cooling chamber, so...