The first two books of the Elements of Euclid, with additional figures, notes, explanations, and deductions, by N. Pocock1852 |
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Page 10
... joining two of its opposite angles . Fig . 1 . Fig . 2 . Fig . 3 . [ All the above figures are parallelograms ; those below are not parallelograms , both being four - sided figures . Fig . 4 . has one pair of opposite sides parallel ...
... joining two of its opposite angles . Fig . 1 . Fig . 2 . Fig . 3 . [ All the above figures are parallelograms ; those below are not parallelograms , both being four - sided figures . Fig . 4 . has one pair of opposite sides parallel ...
Page 15
... join CA , CB . A B Before proceeding further , practise drawing equilateral triangles as follows : - Having made the triangle ABC , describe another equilateral triangle on the opposite F C D side of AB , and also one on BC and on AC ...
... join CA , CB . A B Before proceeding further , practise drawing equilateral triangles as follows : - Having made the triangle ABC , describe another equilateral triangle on the opposite F C D side of AB , and also one on BC and on AC ...
Page 19
... join the points E and F by the use of a pen and straight ruler . It will be seen that the points E and F coinciding with B and C , the whole line BC will exactly coincide with EF , unless it be possible for two straight lines to enclose ...
... join the points E and F by the use of a pen and straight ruler . It will be seen that the points E and F coinciding with B and C , the whole line BC will exactly coincide with EF , unless it be possible for two straight lines to enclose ...
Page 20
... join FC , GB . Because AF is equal to AG , and AB to AC , the two sides FA , AC are equal to the two GA , AB , each to each ; and they contain the angle FAG common to the two triangles AFC , AGB ; therefore the base FC is equal to the ...
... join FC , GB . Because AF is equal to AG , and AB to AC , the two sides FA , AC are equal to the two GA , AB , each to each ; and they contain the angle FAG common to the two triangles AFC , AGB ; therefore the base FC is equal to the ...
Page 21
... Join AC . Then if BC be joined , the triangle BAC will be isosceles , hav- C ing the sides BA , AC equal to each other . ] BOOK I. b iv . 1 . BOOK I. a iii . 1 . b iv . c 3 OF EUCLID . 21 and FC was proved to be equal to GB; ...
... Join AC . Then if BC be joined , the triangle BAC will be isosceles , hav- C ing the sides BA , AC equal to each other . ] BOOK I. b iv . 1 . BOOK I. a iii . 1 . b iv . c 3 OF EUCLID . 21 and FC was proved to be equal to GB; ...
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The First Two Books of the Elements of Euclid, with Additional Figures ... Euclides No preview available - 2016 |
Common terms and phrases
adjacent angles alternate angles angle ABC angle ACB angle AGH angle BAC angle BCD angle EDF angled triangle angles CBA angles equal Arithmetic base BC BC is equal bisected BOOK bound centre cloth coincide Delectus diameter double English Notes equal to BC equal to twice Eton Eton College Euclid's Elements Exercises exterior angle four right angles Geography given point given rectilineal angle given straight line gnomon greater Greek half a right interior and opposite isosceles JANE MARCET join Let ABC Let the straight Lexicon M.A. New Edition Maps opposite angle parallel to CD parallelogram perpendicular Post 8vo produced Proposition rectangle BC rectangle contained rectilineal figure remaining angle rhombus right angles Schools Shrewsbury School sides BA sides equal square described square of AC THEOR triangle ABC twice the rectangle VALPY Valpy's wherefore xxxi
Popular passages
Page 18 - If two triangles have two sides of the one equal to two sides of the...
Page 67 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.
Page 51 - That, if a straight line falling on two straight lines make the interior angles on the same side less than two right angles, the two straight lines, if produced indefinitely, meet on that side on which are the angles less than the two right angles.
Page 109 - ... subtending the obtuse angle, is greater than the squares of the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle between the perpendicular and the obtuse angle. Let ABC be an obtuse-angled triangle, having the obtuse angle ACB, and from the point A let AD be drawn perpendicular to BC produced.
Page 12 - Mrs. R. Lee's Elements of Natural History ; or, First Principles of Zoology : Comprising the Principles of Classification, interspersed with amusing and instructive Accounts of the most remarkable Animals.
Page 53 - To draw a straight line through a given point parallel to a given straight line. Let A be the given point, and BC the given straight line ; it is required to draw a straight line E iR.
Page 76 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Page 34 - ABD, the less to the greater, which is impossible ; therefore BE is not in the same straight line with BC. And in like manner, it may be demonstrated, that no other can be in the same straight line with it but BD, which therefore is in the same straight line with CB.
Page 11 - LET it be granted that a straight line may be drawn from any one point to any other point.
Page 37 - Any two angles of a triangle are together less than two right angles. Let ABC be any triangle ; any two of its angles together are less than two right angles.