Elements of Algebra: Including Sturms' Theorem |
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Page 6
... Quantity . To Reduce Fractions to a Common Denominator . To Add Fractions To Subtract Fractions .. To Multiply ... Unknown Quantities 94-95 95-96 Elimination - By Addition - By Subtraction - By Comparison .... Indeterminate Problems - ...
... Quantity . To Reduce Fractions to a Common Denominator . To Add Fractions To Subtract Fractions .. To Multiply ... Unknown Quantities 94-95 95-96 Elimination - By Addition - By Subtraction - By Comparison .... Indeterminate Problems - ...
Page 60
... unknown quantities of the problem . The SOLUTION of the equation consists in finding such a value for the unknown quantity as being substituted for it in the equa- tion will satisfy it ; that is , make the first member equal to the ...
... unknown quantities of the problem . The SOLUTION of the equation consists in finding such a value for the unknown quantity as being substituted for it in the equa- tion will satisfy it ; that is , make the first member equal to the ...
Page 65
... unknown quantity into the first member , and all the known terms into the second . II . Reduce to a single term all the terms involving the unknown quantity : this term will be composed of two factors , one of which will be the unknown ...
... unknown quantity into the first member , and all the known terms into the second . II . Reduce to a single term all the terms involving the unknown quantity : this term will be composed of two factors , one of which will be the unknown ...
Page 67
... Unknown Quantity . 94. It has already been observed ( Art . 81 ) , that the solution of a problem by Algebra , consists of two distinct parts . 1st . The statement ; and 2d . The solution of the equation . We have already explained the ...
... Unknown Quantity . 94. It has already been observed ( Art . 81 ) , that the solution of a problem by Algebra , consists of two distinct parts . 1st . The statement ; and 2d . The solution of the equation . We have already explained the ...
Page 68
... unknown quantities , as would verify the value of the unknown quantity , were such value known . QUESTIONS . 1. Find a number such , that the sum of one half , one third , and one fourth of it , augmented by 45 , shall be equal to 448 ...
... unknown quantities , as would verify the value of the unknown quantity , were such value known . QUESTIONS . 1. Find a number such , that the sum of one half , one third , and one fourth of it , augmented by 45 , shall be equal to 448 ...
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Common terms and phrases
affected algebraic quantities arithmetical arrangements becomes binomial called co-efficient common difference consequently contain continued fraction contrary signs cube root decimal deduced denominator divide dividend division entire number enunciation equa equal equation involving example exponent factors figure formula fourth given equation given number gives greater greatest common divisor hence inequality last term least common multiple less logarithm method monomial multiply nth root number of terms obtain operation ounces perfect square positive roots preceding problem progression proposed equation quan quotient real roots Reduce remainder resolved result rule second degree second member second term simplest form square root substituted subtract superior limit suppose take the equation taken third tion tities transformed transposing unity unknown quantity whence whole number
Popular passages
Page 30 - That is, the square of the sum of two quantities is equal to the square of the first, plus twice the product of the first by the second, plus the square of the second.
Page 275 - The characteristic of a number less than 1 is found by subtracting from 9 the number of ciphers between the decimal point and the first significant digit, and writing — 10 after the result.
Page 27 - Hence, for the multiplication of polynomials we have the following RULE. Multiply all the terms of the multiplicand by each term of the multiplier, observing that like signs give plus in the product, and unlike signs minus.
Page 179 - To express that the ratio of A to B is equal to the ratio of C to D, we write the quantities thus : A : B : : C : D; and read, A is to B as C to D.
Page 180 - If the product of two quantities is equal to the product of two other quantities, two of them may be made the extremes, and the other two the means of a proportion.
Page 90 - If A and B together can perform a piece of work in 8 days, A and C together in 9 days, and B and C in 10 days : how many days would it take each person to perform the same work alone ? Ans.
Page 346 - VARIATIONS of signs, nor the number of negative roots greater than the number of PERMANENCES. Consequence. 328. When the roots of an equation are all real, the number of positive roots is equal to the number of variations, and the number of negative roots to , the number of permanences.
Page 34 - I. Divide the coefficient of the dividend by the coefficient of the divisor.
Page 108 - Which proves that the square of a number composed of tens and units, contains the square of the tens plus twice the product of the tens by the units, plus the square of the units.
Page 202 - In each succeeding term the coefficient is found by multiplying the coefficient of the preceding term by the exponent of a in that term, and dividing by the number of the preceding term.