Pure mathematics, Volume 11874 |
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Results 1-5 of 87
Page 13
... Hence , to get the true quotient of 76875 by 6.25 , we must remove the dot from the extreme right of the number 123 , five minus two , or three places to the left . Now three is the excess of the number of decimal figures in the ...
... Hence , to get the true quotient of 76875 by 6.25 , we must remove the dot from the extreme right of the number 123 , five minus two , or three places to the left . Now three is the excess of the number of decimal figures in the ...
Page 18
... hence follows that the fraction is properly expressed by the ratio 12 : 7 . The first term of a ratio is called the antecedent , and the second is called the consequent ; and hence we may consider a fraction as a ratio , the numerator ...
... hence follows that the fraction is properly expressed by the ratio 12 : 7 . The first term of a ratio is called the antecedent , and the second is called the consequent ; and hence we may consider a fraction as a ratio , the numerator ...
Page 20
... hence it follows that 8 x 3 = 989985 It may be remarked that the two results , and § , are of exactly the same value ( Art . 7 ) , since the latter may be ob- tained from the former by dividing each of its terms by 3 . In actual ...
... hence it follows that 8 x 3 = 989985 It may be remarked that the two results , and § , are of exactly the same value ( Art . 7 ) , since the latter may be ob- tained from the former by dividing each of its terms by 3 . In actual ...
Page 22
... Hence the ratio 16:47 is equi- 5 16X9 16X9 = 5 ÷ 5 1 = 16 x 9 . valent to the ratio 16 fraction 16 4.7 = 16X9 . 47 X 5 5 = x 9 : 47 × 5 , and hence the Now 16 and 9 are called the extreme terms of the complex fraction and 5 and 47 are ...
... Hence the ratio 16:47 is equi- 5 16X9 16X9 = 5 ÷ 5 1 = 16 x 9 . valent to the ratio 16 fraction 16 4.7 = 16X9 . 47 X 5 5 = x 9 : 47 × 5 , and hence the Now 16 and 9 are called the extreme terms of the complex fraction and 5 and 47 are ...
Page 23
... Hence we arrive at the result- = 4 of 4 = 3 4 X 7 1x 5 . And in the same way we might show that of of 3 of 11 Hence the rule : - = 7 X 4 X 3 X 11 . 8 X 9 X 5 X 1 RULE . - Multiply together the several numerators for a new numerator ...
... Hence we arrive at the result- = 4 of 4 = 3 4 X 7 1x 5 . And in the same way we might show that of of 3 of 11 Hence the rule : - = 7 X 4 X 3 X 11 . 8 X 9 X 5 X 1 RULE . - Multiply together the several numerators for a new numerator ...
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Common terms and phrases
a²b a²b² a²x² a³b ab² ab³ ABCD adjacent angles algebraical algebraical quantity angle ABC angle BAC angle BCD angle EDF angle equal base BC BC is equal bisect brackets cent centim centre circle ABC coefficient common Const cube root decimal figures denominator distance divided divisor equation expression exterior angle factor Find the value fraction given rectilineal given straight line greater Hence join kilom Let ABC logarithm metres millig Multiply opposite angles parallel parallelogram perpendicular PROOF.-Because Q. E. D. Proposition quotient ratio rectangle contained remainder right angles segment side BC square on AC square root subtraction term triangle ABC x²y x²y² x³y xy² xy³
Popular passages
Page 116 - Wherefore, if a straight line, &c. QED PROPOSITION XXVIII. THEOREM. If a straight line falling upon two other straight lines, make the exterior angle equal to...
Page 103 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Page 113 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Page 88 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Page 273 - The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles.
Page 94 - J which the equal sides are opposite, shall be equal, each to each, viz. the angle ABC to the angle DEF, and the angle ACB to DFE.
Page 271 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle ; the angles which this line makes with the line touching the circle, shall be equal to the angles which are in the alternate segments of the circle.
Page 91 - If a straight line meets two straight lines, so as to " make the two interior angles on the same side of it taken " together less than two right angles...
Page 112 - IMS the greater base shall be greater t/uin the angle contained by the sides equal to them of the other. Let ABC, DEF, be two triangles, which have The two sides AB, AC...
Page 128 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.