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AABC ABCD acute angle adjacent altitude base bisector bisects called chord circle circumscribed coincide common Compute Construct determine diagonals diameter difference distance divided Draw drawn equal equidistant equilateral triangle equivalent EXERCISES exterior external fall figure Find formed four geometric Give given given line given point greater hexagon hypotenuse inch included inscribed interior angles intersecting isosceles triangle joining less mean measure median meet method middle point moves opposite parallel lines parallelogram pass perimeter perpendicular placed plane polygon position Problem Proof proportional Prove quadrilateral radii radius ratio rectangle regular polygon right angle right triangle secant segment Show shown sides similar square straight line SUGGESTION supplementary surface tangent Theorem transversal trapezoid triangle ABC unit vertex vertices
Page 179 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Page 17 - If two triangles have two angles and the included side of one equal respectively to two angles and the included side of the other, the triangles are congruent.
Page 145 - In any triangle, the square of a side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of those sides and the projection of the other side upon it.
Page 141 - The square described on the hypotenuse of a right triangle is equivalent to the sum of the squares on the other two sides.
Page 79 - Two triangles are congruent if two sides and the included angle of one are equal respectively to two sides and the included angle of the other.
Page 131 - ... any two parallelograms are to each other as the products of their bases by their altitudes. PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by its altitude.
Page 89 - Theorem. In the same circle or in equal circles, equal chords are equidistant from the center; and of two unequal chords the greater is nearer the center. Given two equal © M, M ' , with chords AB = A'B', AE > A'B', and OC, OD, O'C' ±'s from center 0 to AB, AE, and from center O
Page 83 - ... the third side of the first is greater than the third side of the second.