Plane Geometry |
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Page 5
... Distance Concurrent Lines 61 66 69 73 80 Definitions 84 Methods of Proof . 89 General Exercises . 96 CHAPTER II . THE CIRCLE Definitions 103 Arcs and Chords Tangents and Secants Angle Measurement Problems of Construction Location of ...
... Distance Concurrent Lines 61 66 69 73 80 Definitions 84 Methods of Proof . 89 General Exercises . 96 CHAPTER II . THE CIRCLE Definitions 103 Arcs and Chords Tangents and Secants Angle Measurement Problems of Construction Location of ...
Page 14
... distance between the two points A and B. 10. Circle . Place one point A of the compasses on a point A B O , and adjust the compasses until the other point B falls on point D. Keeping the point at O stationary , move point B around point ...
... distance between the two points A and B. 10. Circle . Place one point A of the compasses on a point A B O , and adjust the compasses until the other point B falls on point D. Keeping the point at O stationary , move point B around point ...
Page 15
... distance between the two points of the compasses is not changed during the construction of a circle , all radii of the same circle are equal . It follows that , all points on a circle are equidistant from the center . 12. Laying off ...
... distance between the two points of the compasses is not changed during the construction of a circle , all radii of the same circle are equal . It follows that , all points on a circle are equidistant from the center . 12. Laying off ...
Page 20
... distance from a point B to an inaccessible point A may be found , as shown in the figure . AN Any distance as BC is laid off from B. Zx is found by observation and Zy is made equal to Zx . Similarly Zz is made equal to ≤r . ADBC = AABC ...
... distance from a point B to an inaccessible point A may be found , as shown in the figure . AN Any distance as BC is laid off from B. Zx is found by observation and Zy is made equal to Zx . Similarly Zz is made equal to ≤r . ADBC = AABC ...
Page 24
... bridges , much use is made of the triangle , as the " unit of rigidity . " Why is it possible for this bridge to be supported on a pier at the center ? C * 10 . Show how to find the distance between. 24 PLANE GEOMETRY.
... bridges , much use is made of the triangle , as the " unit of rigidity . " Why is it possible for this bridge to be supported on a pier at the center ? C * 10 . Show how to find the distance between. 24 PLANE GEOMETRY.
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Common terms and phrases
AABC ABCD acute angle ADEF adjacent angles altitude angle equal angles are equal base bisects chord circumference circumscribed coincide Construct a square corresponding sides decagon diagonals diameter distance divided Draw equal angles equal respectively equal sides equilateral triangle EXERCISES exterior external point figure Find the area Find the length geometric given circle given line given point hexagon hypotenuse inch inscribed angle interior angles intersecting isosceles trapezoid isosceles triangle median middle point number of degrees number of sides parallel lines parallelogram pentagon perigon perimeter perpendicular bisector plane Proof protractor Prove quadrilateral radii radius ratio rectangle reflex angle regular inscribed regular polygon rhombus right angle right triangle secant segment semicircle Show shown sides equal similar triangles straight angle supplementary surface tangent Theorem transversal triangle ABC triangles equal vertex angle vertices
Popular passages
Page 179 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Page 43 - If a straight line is perpendicular to one of two parallel lines, it is perpendicular to the other also.
Page 17 - If two triangles have two angles and the included side of one equal respectively to two angles and the included side of the other, the triangles are congruent.
Page 145 - In any triangle, the square of a side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of those sides and the projection of the other side upon it.
Page 141 - The square described on the hypotenuse of a right triangle is equivalent to the sum of the squares on the other two sides.
Page 79 - Two triangles are congruent if two sides and the included angle of one are equal respectively to two sides and the included angle of the other.
Page 131 - ... any two parallelograms are to each other as the products of their bases by their altitudes. PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by its altitude.
Page 89 - Theorem. In the same circle or in equal circles, equal chords are equidistant from the center; and of two unequal chords the greater is nearer the center. Given two equal © M, M ' , with chords AB = A'B', AE > A'B', and OC, OD, O'C' ±'s from center 0 to AB, AE, and from center O
Page 83 - ... the third side of the first is greater than the third side of the second.
Page 188 - If two chords intersect in a circle, the product of the segments of one is equal to the product of the segments of the other.