Plane Geometry |
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Page 66
... decagon . H K M N Twelve sides is a dodecagon . Fifteen sides is a pentadecagon . CONVEX POLYGON CONCAVE POLYGON 169 ... decagon . 2. Show by a drawing , how many diagonals can be drawn from one vertex in each polygon of Exercise 1. How ...
... decagon . H K M N Twelve sides is a dodecagon . Fifteen sides is a pentadecagon . CONVEX POLYGON CONCAVE POLYGON 169 ... decagon . 2. Show by a drawing , how many diagonals can be drawn from one vertex in each polygon of Exercise 1. How ...
Page 68
... decagon , a pentadecagon . 2. Find the value of each interior angle and each exterior angle of a regular pentagon , hexagon , octagon , decagon , pentadecagon , and also of a regular polygon of twenty sides . Tabulate results of ...
... decagon , a pentadecagon . 2. Find the value of each interior angle and each exterior angle of a regular pentagon , hexagon , octagon , decagon , pentadecagon , and also of a regular polygon of twenty sides . Tabulate results of ...
Page 235
... Then § 407 HK HB But HC - HK = HA . Why ? And HK - HB - AK . Why ? НА АК Whence - And HK HA HK HA = HA AK .. HK is divided at A in extreme and mean ratio . § 404 . 470. Problem . To construct a regular decagon in a REGULAR POLYGONS . 235.
... Then § 407 HK HB But HC - HK = HA . Why ? And HK - HB - AK . Why ? НА АК Whence - And HK HA HK HA = HA AK .. HK is divided at A in extreme and mean ratio . § 404 . 470. Problem . To construct a regular decagon in a REGULAR POLYGONS . 235.
Page 236
... decagon in a given circle . Given the circle with center 0 . Required to inscribe a regular decagon in the given circle . Construction . Draw the radius OA . Divide OA in extreme and mean ratio so OA OC that = ОС СА . § 469 A With A as ...
... decagon in a given circle . Given the circle with center 0 . Required to inscribe a regular decagon in the given circle . Construction . Draw the radius OA . Divide OA in extreme and mean ratio so OA OC that = ОС СА . § 469 A With A as ...
Page 237
... decagon , or polygon of fifteen sides . Discussion . O is the center of the given . circle in which the pentadecagon is to be inscribed . Draw AC the side of a regular inscribed hexagon and AB the side of a regular inscribed decagon ...
... decagon , or polygon of fifteen sides . Discussion . O is the center of the given . circle in which the pentadecagon is to be inscribed . Draw AC the side of a regular inscribed hexagon and AB the side of a regular inscribed decagon ...
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Common terms and phrases
AABC ABCD acute angle ADEF adjacent angles altitude angle equal angles are equal base bisects chord circumference circumscribed coincide Construct a square corresponding sides decagon diagonals diameter distance divided Draw equal angles equal respectively equal sides equilateral triangle EXERCISES exterior external point figure Find the area Find the length geometric given circle given line given point hexagon hypotenuse inch inscribed angle interior angles intersecting isosceles trapezoid isosceles triangle median middle point number of degrees number of sides parallel lines parallelogram pentagon perigon perimeter perpendicular bisector plane Proof protractor Prove quadrilateral radii radius ratio rectangle reflex angle regular inscribed regular polygon rhombus right angle right triangle secant segment semicircle Show shown sides equal similar triangles straight angle supplementary surface tangent Theorem transversal triangle ABC triangles equal vertex angle vertices
Popular passages
Page 179 - The straight line joining the middle points of two sides of a triangle is parallel to the third side, and equal to half of it.
Page 43 - If a straight line is perpendicular to one of two parallel lines, it is perpendicular to the other also.
Page 17 - If two triangles have two angles and the included side of one equal respectively to two angles and the included side of the other, the triangles are congruent.
Page 145 - In any triangle, the square of a side opposite an acute angle is equal to the sum of the squares of the other two sides diminished by twice the product of one of those sides and the projection of the other side upon it.
Page 141 - The square described on the hypotenuse of a right triangle is equivalent to the sum of the squares on the other two sides.
Page 79 - Two triangles are congruent if two sides and the included angle of one are equal respectively to two sides and the included angle of the other.
Page 131 - ... any two parallelograms are to each other as the products of their bases by their altitudes. PROPOSITION V. THEOREM. 403. The area of a triangle is equal to half the product of its base by its altitude.
Page 89 - Theorem. In the same circle or in equal circles, equal chords are equidistant from the center; and of two unequal chords the greater is nearer the center. Given two equal © M, M ' , with chords AB = A'B', AE > A'B', and OC, OD, O'C' ±'s from center 0 to AB, AE, and from center O
Page 83 - ... the third side of the first is greater than the third side of the second.
Page 188 - If two chords intersect in a circle, the product of the segments of one is equal to the product of the segments of the other.