EXAMPLE 1. Required the Logarithm of the number 2. Here the next less number is 1, and 2+1 =3= A. and A', or 3=9; then 3)0.868588964 9)0.000004903«ll=0.000000446 9)0.000000545+13=0.000000042 0.00000006115=0.000000004 To this Logarithm 0.301029995 addtheLogarithm of 1=0.000000000 Their Sum=0.301029995=Log. of 2. The manner in which the division is here carried on, may be readily perceived by dividing, in the first place, the given decimal by A, and the succeeding quotients by A”; then letting these quotients remain in their situation, as seen in the example, divide them respectively by the odd numbers, and place the new quotients in a column by themselves. By employing this process, the operation is considerably abbreviated. Log. of To this Logarithm 0.176091259 add the Logarithm of 2=0.301029995 Their Sum=0.477121254=Log. of 3. Then, because the sum of the logarithms of numbers, gives the logarithm of their product; and the difference of the logarithms, gives the logarithm of the quotient of the numbers from the two preceding logarithms, and the logarithm of 10, which is !, a great many logarithms can be easily made, as in the following examples. Example 3. Required the Logarithm of 4. these quo 2=0.301029995 add the Logarithm of 2=0.371029995 The sum=Logarithm of 4=0.602059990 in the er numbers by them operation Example 4. Required the Logarithm of 5. 10+2 being=5, therefore from the Log. of 10=1.000000000 subtract the Log. of 2=0.301029995 the remainder is the Log. of 5=0.698970005 Example 5. Required t'e Logarithm of 6. 6=3x2, therefore to the Logarithm of 3=0.477121254 add the Logarithm of 2=0.301029995 their sum=Log. of 6=0.778151249 Example 6. Required the Logarithm of 8. 8=2', therefore multiply the Logarithm of 2=0,301029995 by 3 The product=Log. of 8=0.903089985 Example 7. Required the Logarithm of 9. 9=3, therefore the Logarithm of 3=0.477121254 being multiplied by 2 the product=Log. of 9=0.934242508 Example 8. Required the Logarithm of 7. Here the next less number is 6, and 7+6=13=A, and A=169. 13)0.868588964 169)0.066814536-1=0.066814536 169)0.000395352+3=0.000131784 169)0.000002339-5=0.000000468 0.00000001427=0.000000002 To this Logarithm=0.066946790 add the Log. of 6=0.778151249 Their sum=0.845098039=Log. of 7. of 12 of 3 and 4. of 14 of 7 and 2. of 15 is equal to the sum of 3 and 5. The Log of 16 of the Logs. of 4 and 4. of 18 of 3 and 6. of 20 of 4 and 5. The Logarithms of the prime numbers, 11, 13, 17, 19, &c. being computed by the foregoing general Rule, the Logarithms of the intermediate numbers are easily found by composition and division. It may, however, be observed, that the operation is shorter in the larger prime numbers ; for when any given number exceeds 400, the fi :st quotient, being added to the Logarithm of its next lesser number, will give the Logarithm sought, true to 8, or 9 places; and therefore it will be very easy to examine any suspected Logarithm in the Tables. For the arrangement of Lngarithms in a Table, the method of finding the Logarithm of any natural number, and of finding the natural number corresponding to any given Logarithm, therein : likewise for particular rules concerning the Indices, the reader will consult Table 1, with its explanation, at the end of this Treatise. MULTIPLICATION. Tro, or more numbers being given, to find their product by Logarithms. RULE. Having found the Logarithms of the given numbers in the Table, add them together, and their sum is the Logarithm of the product; which Logarithm, being found in the Table, will give a natural number, that is, the product required. Whatever is carried from the decimal part of the Logarithm is to be added to the affirmative indices ; but subtracted from the negative. Likewise the indices must be added together, when they are all of the same kind, that is, when they are all affirmative, or all negative; but when they are of dfferent kinds, the difference must be found, which will be of the same denomination with the greater. Example 1. Required the product of 86.25 multiplied by 6.48 Log. of 86.25= 1.935759 Product=558.9=2.747334 Example 2. Required the product of 46.75 and .3275 Log. of 46.75= 1.669782 |