A Treatise of Plane and Spherical Trigonometry: In Theory and Practice ; Adapted to the Use of Students ; Extracted Mostly from Similar Works of Ludlam, Playfair, Vince, and Bonnycastle |
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Page iii
... Triangles Napier's Rules of the Circular Parts Quadrantal Spherical Triangles 65 · 70 75 77 82 100 · 103 · 106 Affections and Properties of Quadrantal Triangles 107 Solution of Right - angled Spherical Triangles 109 Solution of Oblique - ...
... Triangles Napier's Rules of the Circular Parts Quadrantal Spherical Triangles 65 · 70 75 77 82 100 · 103 · 106 Affections and Properties of Quadrantal Triangles 107 Solution of Right - angled Spherical Triangles 109 Solution of Oblique - ...
Page 7
... angle less than a right an- gle , are respectively equal to the sine , tangent , and secant ... right - angled triangles corresponding to one another in fig . 1 and 2 ... triangle ACB being equiangular , is also equilateral ( Cor . 6. 1 ) ...
... angle less than a right an- gle , are respectively equal to the sine , tangent , and secant ... right - angled triangles corresponding to one another in fig . 1 and 2 ... triangle ACB being equiangular , is also equilateral ( Cor . 6. 1 ) ...
Page 8
... right angle , is equal to radius . This is manifest from an inspection of ... angled triangles ¿ Cƒ , BCF are equal ( 26. 1 ) , and bf = BF . 35. In like ... triangles TCA , CA , having the angle BCA or TCA equal to the angle ¿ CD or tCA ...
... right angle , is equal to radius . This is manifest from an inspection of ... angled triangles ¿ Cƒ , BCF are equal ( 26. 1 ) , and bf = BF . 35. In like ... triangles TCA , CA , having the angle BCA or TCA equal to the angle ¿ CD or tCA ...
Page 9
... right - angled triangles BCF , TCA , CKH , having the several acute angles BCF , TCA , CKH equal ( 29. 1 ) , are equiangular ; hence the following analogies are deduced . 1. Cosine CF : sine BF :: radius CA : tangent TA . 2. Cosine CF ...
... right - angled triangles BCF , TCA , CKH , having the several acute angles BCF , TCA , CKH equal ( 29. 1 ) , are equiangular ; hence the following analogies are deduced . 1. Cosine CF : sine BF :: radius CA : tangent TA . 2. Cosine CF ...
Page 10
... triangle ABD will be right - angled at B ( 31. 3 ) , and will be divided by BF , a perpen- dicular drawn from the right angle to the base , into two triangles AFB , DFB , similar to the tri- D angle ABD , and to each B M L A C F other ...
... triangle ABD will be right - angled at B ( 31. 3 ) , and will be divided by BF , a perpen- dicular drawn from the right angle to the base , into two triangles AFB , DFB , similar to the tri- D angle ABD , and to each B M L A C F other ...
Common terms and phrases
90 degrees adjacent angle AHDL algebra analogy angle ABC angle ACB Answer arc or angle base centre chord circle comp complement cosecant cosine cotangent Euclid's Elements find the angles find the rest geometry Given the side greater than 90 half the sum half their difference height Hence hypothenuse AC included angle less than 90 logarithmic sines mathematics measured mechanical philosophy negative opposite angle perp perpendicular plane triangle plane trigonometry PROP propositions quadrant AH quantity right-angled spherical triangle right-angled triangle Scholium secant side AB side AC sides and angles sine a sine sine and cosine sine² sines and tangents solution spherical angle spherical triangle ABC spherical trigonometry supplement tables tangent of half theorems third side three angles three sides triangle are given trigono versed sine yards
Popular passages
Page 12 - In every plane triangle, the sum of two sides is to their difference as the tangent of half the sum of the angles opposite those sides is to the tangent of half their difference.
Page ix - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Page 23 - Then multiply the second and third terms together, and divide the product by the first term: the quotient will be the fourth term, or answer.
Page 13 - In any triangle, twice the rectangle contained by any two sides is to the difference between the sum of the squares of those sides, and the square of the base, as the radius to the cosine of the angle included by the two sides. Let ABC be any triangle, 2AB.BC is to the difference between AB2+BC2 and AC2 as radius to cos.
Page 87 - The cosine of half the sum of two sides of a spherical triangle is to the cosine of half their difference as the cotangent of half the included angle is to the tangent of half the sum of the other two angles. The sine of half the sum of two sides of a spherical...
Page 74 - The sum of any two sides is greater than the third side, and their difference is less than the third side.