A Supplement to the Elements of Euclid |
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Page xx
... parallelogram . parallelograms . A : B .... the ratio of A to B. A : B :: C : D the ratio of A to B is equivalent ... ......... to the ratio of C to D. therefore . parallel to A SUPPLEMENT TO THE ELEMENTS OF EUCLID . BOOK I. AN EXPLANATION.
... parallelogram . parallelograms . A : B .... the ratio of A to B. A : B :: C : D the ratio of A to B is equivalent ... ......... to the ratio of C to D. therefore . parallel to A SUPPLEMENT TO THE ELEMENTS OF EUCLID . BOOK I. AN EXPLANATION.
Page 21
... parallelogram . Let any two opposite sides , as AB , DC , of A D B the quadrilateral figure ABCD , be equal to one another , and let the two remaining sides , AD , BC , be , also , equal to one another : The figure ABCD is a . For ...
... parallelogram . Let any two opposite sides , as AB , DC , of A D B the quadrilateral figure ABCD , be equal to one another , and let the two remaining sides , AD , BC , be , also , equal to one another : The figure ABCD is a . For ...
Page 22
... parallelogram . PROP . XIX . 29. THEOREM . Every parallelogram which has one angle a right angle , has all its angles right angles . Let one , as A , of the ABCD be a right angle : The B , C , and D are also right angles . A D B For ...
... parallelogram . PROP . XIX . 29. THEOREM . Every parallelogram which has one angle a right angle , has all its angles right angles . Let one , as A , of the ABCD be a right angle : The B , C , and D are also right angles . A D B For ...
Page 43
... parallelogram . Let AB be a quadrilateral figure , having the A C D B angle A equal to the opposite angle B , and the angle C to the opposite angle D : The figure ADBC is a parallelogram . For , ( E. 32. 1. Cor . 1. ) ELEMENTS OF EUCLID .
... parallelogram . Let AB be a quadrilateral figure , having the A C D B angle A equal to the opposite angle B , and the angle C to the opposite angle D : The figure ADBC is a parallelogram . For , ( E. 32. 1. Cor . 1. ) ELEMENTS OF EUCLID .
Page 50
... . The diameters of a parallelogram bisect each other . Let AB and CD be the diameters of the E D B ADBC ; AB and CD bisect one another in the point of their intersection E. For since ADBC is a □ , AD = CB 50 A SUPPLEMENT TO THE.
... . The diameters of a parallelogram bisect each other . Let AB and CD be the diameters of the E D B ADBC ; AB and CD bisect one another in the point of their intersection E. For since ADBC is a □ , AD = CB 50 A SUPPLEMENT TO THE.
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Common terms and phrases
base BC bisect centre chord circle ABC circle described circumference constr decagon describe a circle describe the circle diameter distance divided double draw a straight draw E equi equiangular equilateral and equiangular F draw find a point finite straight line given circle given finite straight given point given ratio given square given straight line half hypotenuse inscribed isosceles less Let AB Let ABC lines be drawn magnitudes manifest manner meet the circumference number of equal number of sides parallel to BC parallelogram pass perimeter polygon PROBLEM produced PROP rectangle contained rectilineal figure remaining sides required to describe required to draw rhombus right angles segment semi-diameter straight line joining subtend tangent THEOREM three given touch the circle trapezium vertex
Popular passages
Page 310 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Page 198 - If a straight line be bisected, and produced to any point ; the rectangle contained by the whole line thus produced, and the part of it produced, together with the square...
Page 366 - If from the vertical angle of a triangle a straight line be drawn perpendicular to the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the perpendicular and the diameter of the circle described about the...
Page 92 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line.
Page 284 - And if the first have a greater ratio to the second, than the third has to the fourth, but the third the same ratio to the fourth, which the fifth has to the sixth...
Page 349 - Divide a straight line into two parts such that the rectangle contained by the whole line and one of the parts shall be equal to the square on the other part.
Page 288 - Convertendo, by conversion ; when there are four proportionals, and it is inferred, that the first is to its excess above the second, as the third to its excess above the fourth.
Page 296 - ... line and the extremities of the base have the same ratio which the other sides of the triangle have to one...
Page 367 - Wherefore, in equal circles &c. QED PROPOSITION B. THEOREM If the vertical angle of a triangle be bisected by a straight line which likewise cuts the base, the rectangle contained by the sides of the triangle is equal to the rectangle contained by the segments of the base, together with the square on the straight line which bisects the angle.
Page 104 - In every triangle, the square of the side subtending any of the acute angles is less than the squares of the sides containing that angle by twice the rectangle contained by either of these sides, and the straight line intercepted between the perpendicular let fall upon it from the opposite angle, and the acute angle. Let ABC be any triangle, and the angle at B one of its acute angles, and upon BC, one of the sides containing it, let fall the perpendicular...