Search Images Maps Play YouTube News Gmail Drive More »
Sign in
Books Books
" J of the square of their difference, then multiply by the hight, and divide as in the last rule. Having the diameter of a circle given, to find the area. RULE. — Multiply half the diameter by half the circumference, and the product is the area ; or,... "
The Theory and Practice of Gauging, Demonstrated in a Short and Easy Method ... - Page 97
by Robert Shirtcliffe - 1740 - 283 pages
Full view - About this book

Sherwin's Mathematical Tables: Contriv'd in an Easy and Comprehensive Manner ...

Henry Sherwin - Logarithms - 1772 - 454 pages
...thereof. Whence we have the following Rule to Meafure any Circle -wbofe Diameter is given. Multip'y the Square of the Diameter by ,7854 •and the Product is nearly the Area thereof. ' If С be the Circumference of any Circle, then fince 3.1416 = с • с с с1 4 í> : i : : С :...
Full view - About this book

A Treatise on the New Method of Land Surveying, with the Improved Plan of ...

Thomas Hornby (land surveyor.) - Surveying - 1827 - 318 pages
...RULE 1st. Multiply half the Circumference by half the Diameter, and the product is the area. RULE 2. Multiply the square of the diameter by .7854 and the product is the area. EXAMPLE. Required the area of the circle whose diameter AB is 600 links. (By Prob. 7th,)...
Full view - About this book

The Locomotive Engine Popularly Explained, and Illustrated by Lithographic ...

William Templeton - Locomotives - 1841 - 112 pages
...balance. THE AREA OF THE VALVE. To find the area, or number of square inches in a valve. RULE. — Multiply the square of the diameter by .7854 and the product is the area, — thus, 2.5" = 6.25 X .7854 = 4.9087 the area. THE SMOKE BOX. The shell of the smoke box...
Full view - About this book

Elements of plane (solid) geometry (Higher geometry) and trigonometry (and ...

Nathan Scholfield - 1845 - 894 pages
...the circle re quired. Or thus : 31.4159 x^ =78.5398 as before. RULE II. — When the diameter only is given. Multiply the square of the diameter by .7854, and the product will be the area of the circle. For the ratio of the square described on the diameter of a circle,...
Full view - About this book

The Decorator's assistant

458 pages
...7539.8160 125.6636 = 125 ft. 8 in. nearly = arc. PROBLEM XII. To find the area of a circle. 1. When the diameter is given, multiply the square of the diameter by .7854, and the product will be the area. 2. When the circumference and diameter both are given, multiply half the circumference...
Full view - About this book

The locomotive engine popularly explained

William Templeton (engineer.) - 1848 - 118 pages
...balance. THE AREA OF THE VALVE. To find the area, or number of square inches in a ralve. RULE. — Multiply the square of the diameter by .7854 and the product is the area, — thus, 2.5" = 6.25 X .7854 = 4.9087 the area. THE SMOKE BOX. The shell of the smoke box...
Full view - About this book

Mensuration and Practical Geometry: Containing Tables of Weights and ...

Charles Haynes Haswell - Measurement - 1858 - 350 pages
...7, so is the circumference to the diameter. To ascertain the Area of a Circle (Fig. 22). RULE. — Multiply the square of the diameter by .7854, and the product is the area. Or, multiply the square of the circumference by .07958. Or, multiply half the circumference...
Full view - About this book

Orton's Lightning Calculator, and Accountant's Assistant: The Shortest ...

Hoy D. Orton - Mathematics - 1866 - 202 pages
...the diameter by half the circumference, and the product is the area ; or, which is the same thing, multiply the square of the diameter by .7854, and the product is the area. To find the solidity of a sphere or globe. RULE. — Multiply tJie cube of the diameter by...
Full view - About this book

A Practical Workshop Companion for Tin, Sheet Iron, and Copper Plate Workers...

Leroy J. Blinn - Sheet-metal work - 1866 - 216 pages
...product is the Circumference. 2. Multiply the circumference by 81831, the product is the diameter. 3. Multiply the square of the diameter by .7854, and the product is the area. 4. Multiply the square root of the area by 1.12837, the product ia the diameter. 5. Multiply...
Full view - About this book

Orton's Lightning Calculator and Accountant's Assistant

Hoy D. Orton - Ready-reckoners - 1871 - 202 pages
...the diameter by half the< circumference, and the product is the area; ort. which is /he same thing, multiply the square of the? diameter by .7854, and the product is the area. To find the solidity of a sphere or globe. RULE. — Multiply the cube of the diameter ojf....
Full view - About this book




  1. My library
  2. Help
  3. Advanced Book Search
  4. Download EPUB
  5. Download PDF