Elementary Geometry: Plane |
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Results 1-5 of 47
Page 18
... proof of the theorem . Each step in the demonstration must be authorized by something previously accepted as true . 36. A corollary to a theorem is a statement whose truth follows at once from the truth of the theorem , or which can be ...
... proof of the theorem . Each step in the demonstration must be authorized by something previously accepted as true . 36. A corollary to a theorem is a statement whose truth follows at once from the truth of the theorem , or which can be ...
Page 20
... proof are next indicated , and are usually dotted in the drawing to distin- guish them from the lines mentioned in the hypothesis , which are drawn full . The successive steps in the demonstration leading from hypothesis to conclusion ...
... proof are next indicated , and are usually dotted in the drawing to distin- guish them from the lines mentioned in the hypothesis , which are drawn full . The successive steps in the demonstration leading from hypothesis to conclusion ...
Page 22
... Proof . The complement of each angle is obtained by subtracting it from a right angle ( def . , 47 ) . Now all right angles are equal ( theor . 2 , 42 ) ; and if equal angles are subtracted from equal angles , the remainders are equal ...
... Proof . The complement of each angle is obtained by subtracting it from a right angle ( def . , 47 ) . Now all right angles are equal ( theor . 2 , 42 ) ; and if equal angles are subtracted from equal angles , the remainders are equal ...
Page 23
... proof by exclusion . It may be noticed that the two statements above , " OC is the prolonga- tion of 04 , " and " oc ... proof or proof by exclusion . MCM . ELEM . GEOM . — - 3 54. Converse theorems . There is a close relation between ...
... proof by exclusion . It may be noticed that the two statements above , " OC is the prolonga- tion of 04 , " and " oc ... proof or proof by exclusion . MCM . ELEM . GEOM . — - 3 54. Converse theorems . There is a close relation between ...
Page 26
... Proof . Suppose , if possible , that the opposite sides are equal . Then the angles opposite these sides are equal ( 59 ) . This is inconsistent with the hypothesis . Therefore the supposi- tion made is false . Hence the opposite sides ...
... Proof . Suppose , if possible , that the opposite sides are equal . Then the angles opposite these sides are equal ( 59 ) . This is inconsistent with the hypothesis . Therefore the supposi- tion made is false . Hence the opposite sides ...
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Common terms and phrases
ABCD adjacent sides altitude angle AOB angle equal angles are equal antecedents apothem base bisector bisects called central angle central line chord circumscribed circles coincide contraposite corresponding sides Definition diagonal difference divided Draw drawn equal angles equal circles equal ratios equiangular equilateral polygon equivalent figure geometry given angle given circle given line given point given polygon given ratio greater half Hence hypotenuse hypothesis inscribed interior angles intersect isosceles triangle less Let ABC line joining line-segments magnitudes measure-number mid-point mth multiple n-gon number of sides number-correspondent opposite sides parallel parallelogram perigon perimeter perpendicular PROBLEM prolonged prove quadrangle radii radius ratio compounded ratio of similitude regular polygons respectively equal rhombus right angle right triangle segments Show similar polygons similar triangles similarly solution statement straight angle straight line subtended superposable surface symmetric tangent THEOREM triangle ABC unequal vertex vertical angle
Popular passages
Page 148 - In every triangle, the square on the side subtending an acute angle is less than the sum of the squares on the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the perpendicular let fall on it from the opposite angle, and the acute angle.
Page 147 - In an obtuse-angled triangle the square on the side opposite the obtuse angle is greater than the sum of the squares on the other two sides by twice the rectangle contained by either side and the projection on it of the other side.
Page 7 - LET it be granted that a straight line may be drawn from any one point to any other point.
Page 136 - If a straight line be divided into any two parts, the square on the whole line is...
Page 195 - UPON a given straight line to describe a segment of a circle containing an angle equal to a given rectilineal angle.
Page 80 - The straight line joining the middle points of two sides of a triangle is parallel to the third side and equal to half of it 46 INTERCEPTS BY PARALLEL LINES.
Page 305 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Page 287 - ... they have an angle of one equal to an angle of the other and the including sides are proportional; (c) their sides are respectively proportional.
Page 263 - If four magnitudes of the same kind be proportionals, they shall also be proportionals when taken alternately. Let A, B, C, D be four magnitudes of the same kind, which are proportionals, viz.
Page 32 - At a given point in a given straight line, to construct an angle equal to a given angle. Let A be the given point in the straight line AB, and O the given angle.