Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous Practical Problems |
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Page 20
... AB meet the lines BD and BE at the com- mon point B , making the sum of the two angles ABD , ABE , equal to two right angles ; we are to prove that DB and BE are one straight line . т E B • If DB and BE are not in the same 20 GEOMETRY .
... AB meet the lines BD and BE at the com- mon point B , making the sum of the two angles ABD , ABE , equal to two right angles ; we are to prove that DB and BE are one straight line . т E B • If DB and BE are not in the same 20 GEOMETRY .
Page 21
... . 3 ) . In like manner , we can prove that AED is equal to CEB . Hence the theorem .; if the two lines intersect each other , the vertical angles must be equal . Second Demonstration . By Def . 11 , the angle BOOK I. 21.
... . 3 ) . In like manner , we can prove that AED is equal to CEB . Hence the theorem .; if the two lines intersect each other , the vertical angles must be equal . Second Demonstration . By Def . 11 , the angle BOOK I. 21.
Page 22
... prove AED = CEB . Hence the theorem ; if two lines intersect each other , the vertical angles must be equal . THEOREM V. If a straight line intersects two parallel lines , the sum of the two interior angles on the same side of the ...
... prove AED = CEB . Hence the theorem ; if two lines intersect each other , the vertical angles must be equal . THEOREM V. If a straight line intersects two parallel lines , the sum of the two interior angles on the same side of the ...
Page 23
... prove that the angle AGH is equal to the alternate angle GHD , and CHG HGB . = By Th . 5 , LB GH + L GHD = two right angles . Al- A H E F B 80 , by Th . 1 , LAGH + LBGH = two right angles . : From these equals take away the common angle ...
... prove that the angle AGH is equal to the alternate angle GHD , and CHG HGB . = By Th . 5 , LB GH + L GHD = two right angles . Al- A H E F B 80 , by Th . 1 , LAGH + LBGH = two right angles . : From these equals take away the common angle ...
Page 25
... each of these by a . Now we are to prove that the three angles B , b , and a , and also that the three angles A , a , and b , are equal to two right angles THEOREM IX . The opposite angles of any parallelogram are BOOK I. 27.
... each of these by a . Now we are to prove that the three angles B , b , and a , and also that the three angles A , a , and b , are equal to two right angles THEOREM IX . The opposite angles of any parallelogram are BOOK I. 27.
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Common terms and phrases
ABCD altitude angle opposite axis bisected chord circle circumference circumscribed common cone convex surface cos.a cos.b cos.c Cosine Cotang diagonal diameter dicular difference distance divided draw equal angles equation equiangular equivalent find the angles formulæ four magnitudes frustum given line greater half Hence the theorem homologous hypotenuse included angle inscribed intersect isosceles less Let ABC logarithm measured multiplied N.sine number of sides opposite angles parallelogram parallelopipedon pendicular perpen perpendicular plane ST polyedron PROBLEM produced Prop proportion PROPOSITION prove pyramid quadrantal radii radius rectangle regular polygon right angles right-angled spherical triangle right-angled triangle SCHOLIUM secant segment similar sin.a sin.b sin.c sine solid angles sphere SPHERICAL TRIGONOMETRY straight line subtracting Tang tangent three angles three sides triangle ABC triangular prisms TRIGONOMETRY vertex vertical angle volume
Popular passages
Page 320 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Page 65 - If four magnitudes are in proportion, the sum of the first and second is to their difference as the sum of the third and fourth is to their difference.
Page 121 - In a given circle to inscribe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle ; it is required to inscribe in the circle ABC a triangle equiangular to the triangle DEF.
Page 56 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Page 34 - Conversely: if two angles of a triangle are equal, the sides opposite to them are equal, and the triangle it itosceles.
Page 126 - To inscribe a regular polygon of a certain number of sides in a given circle, we have only to divide the circumference into as many equal parts as the polygon has sides : for the arcs being equal, the chords AB, BC, CD, &c.
Page 22 - If two parallel lines are cut by a third straight line, the sum of the two interior angles on the same side of the secant line is equal to two right angles.
Page 277 - The logarithm of any power of a number is equal to the logarithm of the number multiplied by the exponent of the power.
Page 94 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 30 - Therefore all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.