Elements of Geometry, and Plane and Spherical Trigonometry: With Numerous Practical Problems |
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Page 15
... half of the diameter . All the diameters of a circle are equal , as are also all the radii . 52. An Arc of a circle is any portion of the circum- ference . 53. An angle having its vertex at the center of a circle is measured by the arc ...
... half of the diameter . All the diameters of a circle are equal , as are also all the radii . 52. An Arc of a circle is any portion of the circum- ference . 53. An angle having its vertex at the center of a circle is measured by the arc ...
Page 42
... half the parallelogram ABEC , and the △ ABF is one half the parallelogram ABDF ; and halves of equals are equal , ( Ax . 7 ) ; there- fore the △ ABE the △ ABF . = Hence the theorem ; triangles on the same base , etc. THEOREM XXIX ...
... half the parallelogram ABEC , and the △ ABF is one half the parallelogram ABDF ; and halves of equals are equal , ( Ax . 7 ) ; there- fore the △ ABE the △ ABF . = Hence the theorem ; triangles on the same base , etc. THEOREM XXIX ...
Page 43
... half of the parallelogram AC , and the △ EFG is one half of the equivalent parallelogram FH ; therefore , the △ ABD — the △ EFG , ( Ax . 7 ) . THEOREM XXX . If a triangle and a parallelogram are upon the same or equal bases , and ...
... half of the parallelogram AC , and the △ EFG is one half of the equivalent parallelogram FH ; therefore , the △ ABD — the △ EFG , ( Ax . 7 ) . THEOREM XXX . If a triangle and a parallelogram are upon the same or equal bases , and ...
Page 45
... half its altitude ; or by one half of the product of its base by its altitude . A E B Let ABC represent any triangle , AB D its base , and AD , at right angles to AB , its altitude ; now we are to show that the area of ABC is equal to ...
... half its altitude ; or by one half of the product of its base by its altitude . A E B Let ABC represent any triangle , AB D its base , and AD , at right angles to AB , its altitude ; now we are to show that the area of ABC is equal to ...
Page 47
... half of it . THEOREM XXXVII . The square described on the difference of two lines is equiv alent to the sum of the squares described on the two lines di- minished by twice the rectangle contained by the lines . Let AB represent the ...
... half of it . THEOREM XXXVII . The square described on the difference of two lines is equiv alent to the sum of the squares described on the two lines di- minished by twice the rectangle contained by the lines . Let AB represent the ...
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Common terms and phrases
ABCD altitude angle opposite axis bisected chord circle circumference circumscribed common cone convex surface cos.a cos.b cos.c Cosine Cotang diagonal diameter dicular difference distance divided draw equal angles equation equiangular equivalent find the angles formulæ four magnitudes frustum given line greater half Hence the theorem homologous hypotenuse included angle inscribed intersect isosceles less Let ABC logarithm measured multiplied N.sine number of sides opposite angles parallelogram parallelopipedon pendicular perpen perpendicular plane ST polyedron PROBLEM produced Prop proportion PROPOSITION prove pyramid quadrantal radii radius rectangle regular polygon right angles right-angled spherical triangle right-angled triangle SCHOLIUM secant segment similar sin.a sin.b sin.c sine solid angles sphere SPHERICAL TRIGONOMETRY straight line subtracting Tang tangent three angles three sides triangle ABC triangular prisms TRIGONOMETRY vertex vertical angle volume
Popular passages
Page 320 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Page 65 - If four magnitudes are in proportion, the sum of the first and second is to their difference as the sum of the third and fourth is to their difference.
Page 121 - In a given circle to inscribe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle ; it is required to inscribe in the circle ABC a triangle equiangular to the triangle DEF.
Page 56 - If a straight line be divided into two equal parts, and also into two unequal parts; the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.
Page 34 - Conversely: if two angles of a triangle are equal, the sides opposite to them are equal, and the triangle it itosceles.
Page 126 - To inscribe a regular polygon of a certain number of sides in a given circle, we have only to divide the circumference into as many equal parts as the polygon has sides : for the arcs being equal, the chords AB, BC, CD, &c.
Page 22 - If two parallel lines are cut by a third straight line, the sum of the two interior angles on the same side of the secant line is equal to two right angles.
Page 277 - The logarithm of any power of a number is equal to the logarithm of the number multiplied by the exponent of the power.
Page 94 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Page 30 - Therefore all the interior angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.