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sin AB for BD
cos AB for OD
tan AB for AC

sec AB for OC.
49. If ABE be equal to a quad- G
rant, or 90', then EB will be the
complement of AB. Let the lines
ET and IB be drawn perpendicular
to OE. Then,

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ET, the tangent of EB, is called the cotangent of AB;
IB, the sine of EB, is equal to the cosine of AB;

OT, the secant of EB, is called the cosecant of AB. In general, if A is any arc or angle, we have,

cos A=sin (900 A)

cot A=tan (900- A)

cosec A=sec (900 - A) 50. If we take an arc ABEF, greater than 90', its sine will be FH; OH will be its cosine; AQ its tangent, and OQ its secant. But FH is the sine of the arc GF, which is the supplement of AF, and OH is its cosine : hence, the sine of an arc is equal to the sine of its supplement; and the cosine of an arc is equal to the cosine of its supplement.*

Furthermore, AQ is the tangent of the arc AF, and OQ is its secant: GL is the tangent, and OL the secant, of the supplemental arc GF. But since AQ is equal to GL, and OQ to OL, it follows that, the tangent of an arc is equal to the tangent of its supplement ; and the secant of an arc is equal to the secant of its supplement.*

Let us suppose, that in a circle of a given radius, the lengths of the sine, cosine, tangent, and cotangent, have been calculated for every minute or second of the quadrant, and arranged in a table; such a table is called a table of sines and tangents. If the radius of the circle is 1, the table is called a table of natural sines. A table of natural sines, therefore, shows the

*

* These relations are between the values of the trigonometrical lines; the values of the sines, cosines, tangents and cotangents of all the arcs of a quadrant, divided to minutes or seconds.

If the sines, cosines, tangents and secants are known for arcs less than 90°, those for arcs which are greater can be found from them. For if an arc is less than 90', its supplement will be greater than 90', and the values of these lines are the same for an arc and its supplement. Thus, if we know the sine of 20', we also know the sine of its supplement 160°; for the two are equal to each other.

TABLE OF LOGARITHMIC SINES.

51. In this table are arranged the logarithms of the numerical values of the sines, cosines, tangents and cotangents of all the arcs of a quadrant, calculated to a radius of 10,000,000,000. The logarithm of this radius is 10. In the first and last horizontal lines of each page, are written the degrees whose sines, cosines, &c. are expressed on the page. The vertical columns on the left and right, are columns of minutes.

CASE I.

To find, in the table, the logarithmic sine, cosine, tangent, or

cotangent of any given arc or angle. 52. If the angle is less than 45°, look for the degrees in the first horizontal line of the different pages : then descend along the column of minutes, on the left of the page, till you reach the number showing the minutes : then pass along the horizontal line till you come into the column designated, sine, cosine, tangent, or cotangent, as the case may be : the number so indicated is the logarithm sought. Thus, on page 37, for 19° 55' we find, sin 19° 55'

9.532312 cos 19° 55'

9.973215 tan 19° 55'

9.559097 cot 19° 55'

10.440903 53. If the angle is greater than 45', search for the degrees along the bottom line of the different pages : then, ascend along the column of minutes on the right hand side of the page, till you reach the number expressing the minutes : then pass along the horizontal line into the columns designated

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tang, cot, sine, or cosine, as the case may be ; the number so pointed out is the logarithm required.

54. The column designated sine, at the top of the page, is designated cosine at the bottom; the one designated tang, by cotang, and the one designated cotang, by tang.

The angle found by taking the degrees at the top of the page

and the minutes from the first vertical column on the left, is the complement of the angle found by taking the corresponding degrees at the bottom of the page, and the minutes traced up in the right hand column to the same horizontal line. Therefore, sine, at the top of the page, should correspond with cosine, at the bottom; cosine with sine, tang with cotang, and cotang with tang, as in the tables (Art. 49).

If the angle is greater than 90', we have only to subtract it from 180', and take the sine, cosine, tangent or cotangent of the remainder.

The column of the table next to the column of sines, and on the right of it, is designated by the letter D. This column is calculated in the following manner.

Opening the table at any page, as 42, the sine of 24° is found to be 9.609313 ; that of 24° 01', 9.609597: their difference is 284 ; this being divided by 60, the number of seconds in a minute, gives 4.73, which is entered in the column D, omitting the decimal point.

Now, supposing the increase of the logarithmic sine to be proportional to the increase of the arc, and it is nearly so for 60", it follows, that 473 (the last two places being regarded as decimals), is the increase of the sine for 1". Similarly, if the are were 24° 20' the increase of the sine for 1", would be 465, the last two places being decimals.

The same remarks are equally applicable in respect of the column D, after the column cosine, and of the column D, between the tangents and cotangents. The column D, between the columns tangents and cotangents, answers to both of these columns.

Now, if it were required to find the logarithmic sine of an arc expressed in degrees, minutes, and seconds, we have only to find the degrees and minutes as before; then, multiply the corresponding tabular number by the seconds, cut off two places to the right hand for decimals, and then add the pro

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Thus, if we wish the sine of 40° 26' 28".
The sine 40° 26'

9.811952 Tabular difference 247 Number of seconds 28 Product 69 16 to be added

69.16 Gives for the sine of 40° 26' 28"

9.812021. The decimal figures at the right are generally omitted in the last result ; but when they exceed five-tenths, the figure on the left of the decimal point is increased by 1; this gives the result to the nearest unit.

The tangent of an arc, in which there are seconds, is found in a manner entirely similar. In regard to the cosine and cotangent, it must be remembered, that they increase while the arcs decrease, and decrease as the arcs are increased ; consequently, the proportional numbers found for the seconds, must be subtracted, not added.

EXAMPLES.

1. To find the cosine of 3° 40' 40" The cosine of 3° 40'

9.999110 Tabular difference 13 Number of seconds 40 Product 5.20 to be subtracted

5.20 Gives for the cosine of 3° 40' 40"

9.999105 2. Find the tangent of 37° 28' 31"

Ans. 9.884592. 3. Find the cotangent of 870 57' 59"

Ans. 8.550356.

CASE 11.

To find the degrees, minutes and seconds, answering to any

given logarithmic sine, cosine, tangent or cotangent. 56. Search in the table, and in the proper column, until the number is found : the degrees will be shown either at the top or bottom of the page, and the minutes in the side columns, either at the left or right.

But, if the number cannot be exactly found in the table, take from the table the degrees and minutes answering to the nearest less logarithm, the logarithm itself, and also the corresponding tabular difference. Subtract the logarithm taken from the table from the given logarithm, annex two ciphers to the remainder, and then divide the remainder by the tabular difference: the quotient will be seconds, and is to be connected with the degrees and minutes before found; to be added for the sine and tangent, and subtracted for the cosine and cotangent.

EXAMPLES.

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1. Find the arc answering to the sine 9.880054 Sine 49° 20', next less in the table 9.879963 Tabular difference

181)9100(50" Hence, the arc 49° 20' 50" corresponds to the given sine 9.880054. 2. Find the arc whose cotangent is 10.008688 cot 44° 26', next less in the table . 10.008591 Tabular difference

421)9700(23" Hence, 44° 26' — 23" =44° 25' 37" is the arc answering to the given cotangent 10.008688. 3. Find the arc answering to tangent 9.979110

Ans. 43° 37' 21" 4. Find the arc answering to cosine 9,944599

Ans. 28° 19' 45". We shall now demonstrate the principal theorems of Plane Trigonometry.

THEOREM I.

The sides of a plane triangle are proportional to the sines of

their opposite angles. 57. Let ABC be a triangle; then will

CB: CA :: sin A : sin B. For, with A as a centre, and AD equal to the less side BC, as a radius, describe the arc DI: and with B as a centre and the equal radius BC,

B A4

EIL F describe the arc CL: now DE is the sine of the angle A, and CF is the sine of B, to the same radius AD or BC. But by similar triangles,

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