L. 8. 8 6 8 d. 2. Multiply 3 13 4 by 31 Product 113 13 4 3. I 18 10 by 68 132 0 4. 111 6 by 23 36 4 5. 16 61 by 47 38 17 5} 6. 16 8 by 112 93 6 When the multiplier is greater than the product of any two factors in the multiplication table, work by RULE 4. Multiply continually by as many tens less one, as there are figures in the multiplier; then multiply the last product by the left hand figure of the multiplier (if greater than 1;) again, multiply the given sum by the units figure of the multiplier, the product of the first ten by the tens figure,—the product of the second ten (if any) by the hundreds figure, &c. then add the products of these several figures together, and their amount will be the product required. See the following 33 4 d. L. 8. d. 3. Multiply 2 by 195 Product 11 7 6 4. 1 3 by 435 27 3 9 5. 3 3 by 407 66 2 9 6. 2 4 by 820 95 13 4 7. 1 3 6 by 165 193 17 6 8 61 by 276 7 9 6 11. by 2123 99 10 APPLICATION. 11. If one pound of sugar cost 1s. Id. what will 4 pounds cost? Ans. 4s. 4d. 2. If one yard of muslin cost 9s. 4jd. what is the price of 7 yards? Ans. 3L. 5s. 74. 3. What will 5 yards of broad cloth come to at 2 L. 55. per yard? Ans. 11L. 5s. 4. What will 9 hundred weight of flour amount to at IL. 11s. 5d. a hundred weight? Ans. . 14L. 2s. 9d. 5. Sold 10 tons of hay, at 8 L. 12s. 61d. a ton, what is the amount ? Ans. 86L. 5s. 5d. 6. How much will 66 acres of land come to at 7L. 95. 6d. an acre ? Ans. 493L. 7s, 7. What will 32 pounds of cheese cost at 3s. 11d. a pound? Ans. 6L. 58. 4d. 3. Bought 63 gallons of wine at 5s. 4d. per gallon; what was the amount ? Ans. 16L. 16s. 9. What is the value of 336 yards of linen at 2s. 5d. per yard? Ans.. 40L. 12s. 10. How much will 240 bushels of wheat come to at 14s. 6d. per bushel? Ans. 174L. 11. If one pound of sugar cost ls. 1d. what will 109 pounds come to ? Áns. 6L. 2s. 7 d. 12. What will 400 pounds of lead come to at 8 d. per pound? Ans. 14L, 3s. 4d. 13. How much will 1500 gallons of oil amount to at 6s. 2d. per gallon. Ans, 462 L. 10s. 14. A goldsmith bought 11 ingots of silver, each of which weighed 4 pounds, 1 ounce, 15 pennyweights, 22 grains. What is the weight of the whole ? Ans. 45 lb. 7 02. 15 dwt. 2 gr. 15. A grocer bought 5 hogsheads of sugar, weighing each 12 cwt. Iqr. 27 lb. How much did the whole weigh? Ans. 62cwt. lqr. 23 lb. 16. Sold 10 pieces of cloth, measuring each 17 yards, 3 quarters, 2 nails. How many yards were, there in all ? Ans. 178 yds. 3 qrs. 17. There are 5 bags of apples, each of which contains 2 bushels, 3 pecks. How many bushels are there in the whole? Ans. 13 bu. 3 pe. COMPOUND DIVISION. Compound Division teaches to divide any sum or quantity which consists of several denominations. When the divisor does not exceed 12, work by RULE 1. Divide the several denominations of the given sum or quantity, one after another, (beginning with the highest) and set their respective quotients underneath : when a remainder occurs on dividing any denomination, reduce it to the next lower denomination, and add it to that denomination in the given sum or quantity. If the number of either denomination be not large enough to contain the divisor, reduce it to the next lower denomination, and add it thereto; then divide as before, and so proceed. PROOF. Multiply the quotient by the divisor, and the product will be equal to the dividend. EXAMPLES. L. 8. d. L. L. & d. L. 8. d. 2) 6 6 4 410 7 4 8)20 2 6)5 2 9 A L. 8. 8. d. L. d. 9. Divide 56 10 7 by 5 Quotient li 6 la 10. 27 13 6 by 8 3 9 9 11. 32 14 0 3 12 8 12. 3 15 0 7 6 15 4 81 + 8 14. 170 0 0 by 6 23 6 8 WEIGHTS AND MEASURES. lb. oz. dwt. gr. T. Cwt. gr. lb. oz. dr. 15 20 3)45 18 3 25 12 3 2)25 9 When the divisor is the exact product of some two factors in the multiplication table, work by RULE 2. Divide by one of said factors, and then divide the quotient by the other factor. If remainders from the lowest denomination occur, proceed with them as directed in note 2, in Simple Division. 8. d. L. L. 8. L. 8. EXAMPLES. 1. Divide 72 L. 168.7 d. by 24 Quotient 3L. 08. 8 d. +6 L. d. 4)72 16 71 672 16 71 6)18 4 14+27 4)12 2 91 6 R. Quotient 3 0 81+1 Proof 3'0 84+1 d. d. 2. Divide 29 15 O by 21 Quotient 1 8 4 3. 30 10 101 by 27 1 2 71/ 4. 134 18 8 by 44 3 1 4 5. 53 10 O by 84 12 84 +36 6. 984 0 0 by 144 6 16 8 When the divisor is more than 12, and not the exact product of any two factors in the multiplication table, work by RULE 3. Divide the highest denomination of the given sum, by rule 2 of Simple Division, and reduce the remainder, if any, to the next lower denomination, adding to it, when reduced, the number there is of that denomination in the given sum ; then divide as before, and so proceed. EXAMPLES. Divide 36L, 168. 3d. by 19 Quotient IL, 188. 9d. L. d. L. 8. do 19) 36 16 3 ( 1 18 9 19 8. |